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vesna_86 [32]
3 years ago
11

Mr. Molier is calculating the semester averages for his history students. he can calculate the average for 20 students in an hou

r. how many minutes does it take him to calculate the average for each student?
Mathematics
1 answer:
AleksandrR [38]3 years ago
6 0
It takes him 3 minutes to calculate the averages for each student
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The table shows data collected to represent the functional relationship between the number of hours an auto factory is open and
olchik [2.2K]

Answer:

{3, 5, 7, 9, 11}

Step-by-step explanation:

Domain of a function is the set of all the allowable values that can be used as an input to the function. In easy words, we can just say this: The set of all the inputs to a function comprises the Domain of the function.

Domain consists of the values of independent variable on which some other variable depends and give some output result. From the given table we can see that there are two variables: Number of hours(x) and the Cars Produced(y).

Number of cars produced depend on the number of hours the auto factory remains open. So, number of hours is the independent or the input variable and all the values of this variable will form the Domain of the function represented by the table.

So, the Domain of the function is: {3, 5, 7, 9, 11}

3 0
3 years ago
Read 2 more answers
Triangle ABC is transformed to obtain triangle A′B′C′:
Lisa [10]

Answer:

Option C is right.

Step-by-step explanation:

Given is a graph with two triangles marked on it.

Triangle ABC is in the I quadrant with vertices (2,2) (2,10) and (8,12)

Triange A'B'C' is in the III quadrant with vertices (-1,-1), (-1,-5) and (-4,-6)

On comparison we find corresponding side of AB is A'B'

Length of AB = 8 and Length of A'B' = 4.

Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2.

Now since moved to III quadrant from I quadrant we find that there is a rotation of triangle ABC about the origin.  The degree of rotation is 180 degrees.

Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2 and then rotating it about the origin by 180 degrees

8 0
3 years ago
Solve each inequality.<br> X+5 &lt; 6 <br> Pls help
agasfer [191]

Answer:

x<1

Step-by-step explanation:

You would just subtract 5 from both sides of the equation. The sign does not flip because you are not multiplying or dividing any negative number across the sign.  So simply x+5 (-5) < 6 (-5). On the left side the 5 would cancel out.  on the other side 6-5 is equal to 1.

Answer:  x<1

3 0
2 years ago
Read 2 more answers
Brad typed in 48 minutes a report that
g100num [7]

Answer:

59.9 words per minute

Step-by-step explanation:

You can round it to 60.

3 0
2 years ago
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A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
2 years ago
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