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attashe74 [19]
3 years ago
9

In a 5% sale, the price of a phone is reduced by £19.4 Find the original price of the phone

Mathematics
1 answer:
gulaghasi [49]3 years ago
4 0

Answer:

The original price of the phone is £388.

Step-by-step explanation:

Since 5% of the price of the phone is reduced, you can simply multiply the reduced number which is £19.4 by 20.  Your final answer should be £388 when you put it on a calculator or do it on a piece of paper.

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What is the standard form equation of the line shown below?
ch4aika [34]
(-1,1)(1,4)
slope = (4 - 1) / (1 - (-1) = 3/(1 + 1) = 3/2

y = mx + b
slope(m) = 3/2
use either of ur points....(1,4)...x = 1 and y = 4
now sub and find b, the y int
4 = 3/2(1) + b
4 = 3/2 + b
4 - 3/2 = b
8/2 - 3/2 = b
5/2 = b

equation is y = 3/2x + 5/2...but we need it in standard form

y = 3/2x + 5/2
-3/2x + y = 5/2.....multiply both sides by -2
3x - 2y = -5 <==== ur standard form equation
3 0
3 years ago
A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou
Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let z be the

\displaystyle z = \frac{x - \mu}{\sigma}.

In this question, x = 5 and \sigma = 2. The equation becomes

\displaystyle z = \frac{5 - \mu}{2}.

To solve for \mu, the mean of this distribution, the only thing that needs to be found is the value of z. Since

The problem stated that P(X \le 5) = 69.85\% = 0.6985. Hence, P(Z \le z) = 0.6985.

The problem is that the normal distribution tables list only the value of P(0 \le Z \le z) for z \ge 0. To estimate  z from P(Z \le z) = 0.6985, it would be necessary to find the appropriate

Since P(Z \le z) = 0.6985 and is greater than P(Z \le 0) = 0.50, z > 0. As a result, P(Z \le z) can be written as the sum of P(Z < 0) and P(0 \le Z \le z). Besides, P(Z < 0) = P(Z \le 0) = 0.50. As a result:

\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}.

Therefore:

\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}.

Lookup 0.1985 on a normal distribution table. The corresponding z-score is 0.52. (In other words, P(0 \le Z \le 0.52) = 0.1985.)

Given that

  • z = 0.52,
  • x =5, and
  • \sigma = 2,

Solve the equation \displaystyle z = \frac{x - \mu}{\sigma} for the mean, \mu:

\displaystyle 0.52 = \frac{5 - \mu}{2}.

\mu = 5 - 2 \times 0.52 = 3.96.

3 0
3 years ago
Tommy has 3 dogs. Last month, he bought 5 pounds of dog food for 7.95, 8 pounds of dog food for 12.72, and 15 pounds of dog food
bija089 [108]

Answer:

The constant cost of dog food is $1.59 per pound.

Step-by-step explanation:

Divide each pound by the cost and you get $1.59

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