All categories

3 years ago

The product of 3/4 and 7/8 is less than 7/8?

1 answer:

7 0

0.65625 is the decimal product of the fractions 3/4 & 7/8 whereas 7/8 can be simplified to 0.875 in decimal form... comparing both the values, we see that 7/8 is greater than the product of 3/4 and 7/8.

You might be interested in

If f(x)=-x^2+3X +5 and g(x)=X^2 +2x, which graph shows the graph of (f+g)(x)?

lana [24]

Answer:

Step-by-step explanation:

+ We find the function (f+g)(x) like

(f+g)(x)= f(x) + g(x) = x^2 +3x+5 + x^2 + 2x = 2x^2 +5x + 5

+ So the graph of (f+g)(x) is a parabole with the sommet (-5/4, 15/8).

Hope that useful for you.

5 0

3 years ago

Let U = {3, 6, 9, 12, 15, 18, 21, 24} and A = {9, 12, 15, 21}. A'

miskamm [114]

Answer:

A¹ = { 3 , 6, 18 , 24}

Step-by-step explanation:

Explanation:-

Universal set

If all the sets under consideration are the subsets of a fixed set 'U' then the set 'U' is called the Universal set.

Given U = {3, 6, 9, 12, 15, 18, 21, 24}

Given A = {9, 12, 15, 21}

Compliment Of A

The Complement of a set A is all the objects that do not belong to set A

The Compliment of A is denoted by A¹

A¹ = U - A

= {3, 6, 9, 12, 15, 18, 21, 24} - {9, 12, 15, 21}

A¹ = { 3 , 6, 18 , 24}

4 0

2 years ago

Determine whether the relation is or is not a function.

soldier1979 [14.2K]

Answer:

Not a function because it does not pass the Vertical Line Test.

5 0

3 years ago

The radius r of a sphere is 12 units. Find the volume of the sphere. Write your answer in terms of pie

Tamiku [17]

https://socratic.org/questions/what-is-the-volume-of-a-sphere-with-a-radius-of-12-units

the answer is on here

6 0

3 years ago

Find the inverse of the matrix , if it exists

Montano1993 [528]

Answer:

So, option A is correct.

Step-by-step explanation:

To find the inverse of the matrix, the formula is:

$A^{-1} = 1/|A| * Adj A$

Inverse of the matrix exists if |A| does not equal to 0

|A| = 7 * 9 -( -2 * -10)

|A| = 63 - 20

|A| = 43

AS |A| ≠ 0

so inverse exist.

now finding Adj A

$Adj A$ = $\left[\begin{array}{cc}9&2\\10&7\end{array}\right]$

$\left[\begin{array}{cc}9/43&2/43\\10/43&7/43\end{array}\right]$

So, option A is correct.

8 0

2 years ago