On Earth, a spring stretches by 5.0 cm when a mass of 3.0 kg is suspended from one end.
2 answers:
Answer:
Mass = 18.0 kg
Explanation:
From Hooke's law,
F = ke
where: F is the force, k is the spring constant and e is the extension.
But, F = mg
So that,
mg = ke
On the Earth, let the gravitational force be 10 m/ .
3.0 x 10 = k x 5.0
30 = 5k
⇒ k = ................ 1
On the Moon, the gravitational force is of that on the Earth.
m x = k x 5.0
= 5k
⇒ k = ............. 2
Equating 1 and 2, we have;
=
m =
= 18.0
m = 18.0 kg
The mass required to produce the same extension on the Moon is 18 kg.
Answer:
18 kg
Explanation:
weight (N) = mass (kg) × gravitational acceleration (m/s²) force (N) = k (spring constant) × extension (m) On Earth, acceleration of gravity is 10 m/s²
weight = 3.0 (kg) × 10 (m/s²) Since weight is a force, the force is 30 N. The value of spring constant is unknown
30 (N) = k × 5 (m) k = 6 (m/N) Spring constant is 6. Now let's find the mass on the Moon
mass (kg) × gravitational acceleration (m/s²) = k (spring constant) × extension (m) Gravitational acceleration of the moon is 1/6 of that on Earth. Earth's g = 10, so Moon's g = 10/6
m × 10/6 = 6 × 5 m = 30/(10/6) m = 18 The mass is 18 kg
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