I did the work for it and I got an area of 136, sorry I don't think I got it.. thought that if I told you before I left you wouldn't pin it to yourself wondering why I just left.. again, my apologies. hope you get the correct answer! :(
Answer:
Step-by-step explanation:
The funtion is:
C(p)= 3(p)+1.07 (1)
where: 3 is the package cost, p is the number of packages and 1.07 is the taxes
the cost could be equal or less than the gift card value so:
C
(2)
Replace 2 en 1
x 1.07
3(p)

14.02\\\\p\leq \frac{14.02}{3} \\\\p\leq 4.67[/tex]
It´s important to aprox the quantity to the minimum value so I can buy 4 packages
The reasonable domain is for all R because any number is a possible value of the independent variable
Answer:
x = -4, 5/2
Step-by-step explanation:
A quadratic can be solved may ways, including graphing, factoring, and the quadratic formula. You can also check possible answers by making use of the relationships between solutions and the coefficients.
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A graph is attached. It shows the solutions to be -4 and 5/2.
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When factored, the equation becomes ...
(2x -5)(x +4) = 0 . . . . . has solutions x=-4, x=5/2 (these make the factors zero)
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Using the quadratic formula, the solutions of ax^2 +bx +c = 0 are found from ...
x = (-b±√(b²-4ac))/(2a)
x = (-3±√(3²-4(2)(-20))/(2(2)) = (-3±√169)/4 = {-16, +10}/4
x = {-4, 5/2}
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For ax^2 +bx +c = 0, the solutions must satisfy ...
product of solutions is c/a = -20/2 = -10
Only the first and last choices have this product.
sum of solutions is -b/a = -3/2
Only the first choice (-4, 5/2) has this sum.
The answer is 20. just multiply, 4/7*35=20.
Answer: C.) Congruent (or third option)