Cody was 165\,\text{cm}165cm165, start text, c, m, end text tall on the first day of school this year, which was 10\%10%10, perc
1 answer:
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Answer:
If we want to expand the brackets, the fraction would be:
Explanation:
First, we can note that:
w² + w - 20 can be factorized as follows:
w² + w - 20 = (w+5)(w-4)
The given expression already has a (w+5) in the denominator, therefore, all we need to do is multiply the denominator by (w-4)
Since we want the new fraction to be equivalent to the original one, therefore, as we multiply the denominator by (w-4), we will also multiply the numerator by (w-4) to ensure that the value of the fraction is unchanged.
Based on the above, the new fraction would be:
If we want to expand the brackets, the fraction would be:
Hope this helps :)
If we want to expand the brackets, the fraction would be:
Explanation:
First, we can note that:
w² + w - 20 can be factorized as follows:
w² + w - 20 = (w+5)(w-4)
The given expression already has a (w+5) in the denominator, therefore, all we need to do is multiply the denominator by (w-4)
Since we want the new fraction to be equivalent to the original one, therefore, as we multiply the denominator by (w-4), we will also multiply the numerator by (w-4) to ensure that the value of the fraction is unchanged.
Based on the above, the new fraction would be:
If we want to expand the brackets, the fraction would be:
Hope this helps :)
Answer:
The first quartile of the strengths of this alloy is 9.055 GPa.
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The strength of an aluminum alloy is normally distributed with mean 10 gigapascals (GPa) and standard deviation 1.4 GPa.
This means that
What is the first [lower] quartile of the strengths of this alloy?
This is the 100/4 = 25th percentile, which is X when Z has a pvalue of 0.25, so X when Z = -0.675.
The first quartile of the strengths of this alloy is 9.055 GPa.