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IgorLugansk [536]
3 years ago
6

what is the equation in slope intercept form of the line that crosses the x-axis at -2 and is perpendicular to the line represen

ted by y equals negative 1/2 x + 3
Mathematics
1 answer:
Verdich [7]3 years ago
6 0

Answer:

y = -2x - 4

Step-by-step explanation:

So we have the x intercept and a line perpendicular to the one we are trying to find.

Perpendicular deals with the slope.  Perpendicular slopes are negative reciprocals of each other, or in other words, if the slope is m the negative reciprocal is -1/m.

the slope of the perpendicular line is 1/2 so that means the negative reciprocal is -2.

x intercept is when y=0, so the point is (-2, 0).  So that means the equation to make this point with the slope of -2 will look like this

y = mx + b

0 = -2*-2 + b

-4 = b

Now to get into the line we just plug in m and b into y = mx + b

y = mx + b

y = -2x - 4

And to check if you plug in -4 you'll get y = 0

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Eddie's Evergreens sells Christmas trees and wreaths. Trees cost 3 dollars more than 4 times the price of each wreath. It costs
kari74 [83]

Answer:

W = 16

T = 67

Step-by-step explanation:

Represent trees with T and wreaths with W

Given

T = 3 + 4 * W

2 * W + T = 99

Solving (a): Cost of W

Substitute 3 + 4 * W for T in the second equation

2*W + 3 + 4 * W = 99

2W + 3 + 4 W = 99

Collect Like Terms

2W + 4 W = 99 - 3

6W = 96

Divide through by 6

W =\frac{96}{6}

W = 16

Hence, each wreath costs $16

Solving (b): Cost of T

T = 3 + 4 * W

Substitute 16 for W

T = 3 + 4 * 16

T = 3 + 64

T = 67

Hence, each tree costs $67

3 0
3 years ago
How do you solve this step-by-step?
gtnhenbr [62]

Answer:

  • 7 1/20

<u>OAmalOHopeO</u>

4 0
2 years ago
I need help solving -13&lt;4x+7
arsen [322]

Answer:

the answer is -5< x

Step-by-step explanation:

you you start by subtracting 7 by both sides leaving you with -20<4x. then then divide both sides by 4 leaving you with -5< x

5 0
3 years ago
Find the missing number (1+_ ÷7+4)÷8=4/7​
GaryK [48]

The answer to (1+_÷7+4)÷8= 4/7 is -3 I believe

3 0
3 years ago
Before sending track and field athletes to the Olympics, the U.S. Holds a qualifying meet. The box plots below show the distance
sleet_krkn [62]

Question:

The options are;

A. The distances in the Olympic final were farther on average.

B. The distances in the Olympic final varied noticeably more than the US qualifier distances

C. The distances in the Olympic final were all greater than the US qualifier distances

D. none of the above

Answer:

The correct option is;

A. The distances in the Olympic final were farther on average.

Step-by-step explanation:

From the options given, we have

A. The distances in the Olympic final were farther on average.

This is true as the sum of the 5 points divided by 5 is more in the Olympic final

B. The distances in the Olympic final varied noticeably more than the US qualifier distances

This is not correct as the difference between the upper and lower quartile in the Olympic final is lesser than in the qualifier

C. The distances in the Olympic final were all greater than the US qualifier distances

This is not correct as the max of the qualifier is more than the lower quartile in the Olympic final

D. none of the above

We have seen a possible correct option in option A

7 0
3 years ago
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