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statuscvo [17]
4 years ago
10

Mrs. Varner deposited q dollars in a bank account that has been earning annual interest. The total value of the account is based

on the function f(x) = q • 1.025x, where x represents the number of years the money has been in the account. If no deposits or withdrawals are made after the initial deposit, which equation represents the total value of the account 5 years from now?
Mathematics
2 answers:
Ray Of Light [21]4 years ago
8 0
The answer is f(x) = q * 1.025<span>x + 5, do you have that?

</span>
babunello [35]4 years ago
8 0

f(x)=q*1.025^x+5 i just took answered the question


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marin [14]

Answer:

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Step-by-step explanation:


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3 years ago
What is the slope of the line represented by the equation y=4/6x-3?
Finger [1]
Your sloe would be 2/3x because that fraction is rise over run so you go up two and over three positive the -3 is your intercept but he fraction simplified is your slope good luck
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3 years ago
(Picture) easy expressions and equations
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Answer: 2,095,220,000

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3 years ago
Mrs. Benson has graded 46 math assignments but has 80% of the assignments left to grade. Mrs. Benson has how many math assignmen
timofeeve [1]

Mrs. Benson has 184 math assignments left to grade.

<u>Step-by-step explanation:</u>

Here we have , Mrs. Benson has graded 46 math assignments but has 80% of the assignments left to grade.We need to find Mrs. Benson has how many math assignments left to grade. Let's find out:

Let total Number of math assignments be x , So According to question 46 math assignments are graded & 80% are left i.e.

⇒ x = 46+\frac{80x}{100}

⇒ x -\frac{80x}{100}= 46

⇒ \frac{100x-80x}{100}= 46

⇒ \frac{20x}{100}= 46

⇒ \frac{x}{5}= 46

⇒ x=230

Now , Assignments left to grade is :

⇒ 230-46

⇒ 184

Therefore , Mrs. Benson has 184 math assignments left to grade.

4 0
3 years ago
The three consecutive terms
Studentka2010 [4]

Answer:

<h3>1</h3>

Step-by-step explanation:

The nth term of an exponential sequence is expressed as ar^n-1

The nth term of a linear sequence is expressed as Tn = a + (n-1)d

a is the first term

r is the common ratio

d is the common difference

n is the number of terms

Let the three consecutive terms  of an exponential sequence be a/r, a and ar

second term of a linear sequence = a +d

third term of a linear sequence = a + 2d

sixth term of a linear sequence = a + 5d

Now if the three consecutive terms  of an exponential sequence are  the second third and sixth terms  of a linear sequence, this is expressed as;

a/r = a + d ..... 1

a = a + 2d ..... 2

ar = a+ 5d .... 3

From 2: a = a + 2d

a-a= 2d

0 = 2d

d = 0/2

d = 0

Substitute d = 0 into equation 1:

From 1: a/r = a + d

a/r = a+0

a/r = a

Cross multiply

a = ar

a/a = r

1 = r

Rearrange

r = 1

<em>Hence the common ratio of the exponential sequence is 1</em>

 

 

5 0
3 years ago
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