Answer is: <span>the maximum mass of sugar that could be dissolved in 1.3 l of water in room temperature is 2652 grams.
</span><span>The solubility of sugar in water in room temperature is 204 g/100 ml.
Make proportion, if 204 grams of sugar dissolve in 100 ml of water, than how much dissolve in 1300 ml of water:
204 g : 100 ml = m(sugar) : 1300 ml.
m(sugar) = 204 g </span>· 1300 ml ÷ 100 ml.
m(sugar) = 2652 g ÷ 1000 g/kg = 2,652 kg.
Answer:
16.5moles of CO2
Explanation:
Molar mass of O2 is 32g/Mol
No of mole = 880/32 = 27.5 moles
27.5 Mol of O2 gives X mole of CO2
5 mole of O2 gives 3 moles of CO2
No of mole of CO2 = (27.5×3)/ 5 = 16.5moles
Electrons travel around the nucleus in fixed energy levels with energies that vary from level to level
