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lora16 [44]
3 years ago
6

What mass of helium is in a 2.00 L balloon at STP? pls help me lol

Chemistry
1 answer:
sertanlavr [38]3 years ago
3 0

Once upon a time there was a lovely

                        princess. But she had an enchantment

                        upon her of a fearful sort which could

                        only be broken by love's first kiss.

                        She was locked away in a castle guarded

                        by a terrible fire-breathing dragon.

                        Many brave knights had attempted to

                        free her from this dreadful prison,

                        but non prevailed. She waited in the

                        dragon's keep in the highest room of

                        the tallest tower for her true love

                        and true love's first kiss. (laughs)

                        Like that's ever gonna happen. What

                        a load of - (toilet flush)

              Allstar - by Smashmouth begins to play. Shrek goes about his

              day. While in a nearby town, the villagers get together to go

              after the ogre.

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PLZ HELP 2 mins left
mrs_skeptik [129]

Answer:

No matter how many times you cut it, its chemical properties won't change and it'll still be paper.

Explanation:

5 0
3 years ago
A balloon has a volume of 6.2 liters at 23.2 C. The balloon is then heated to a temperature of 144.0 C. What is the volume of th
Marina CMI [18]

Answer:

8.7 L

Explanation:

T2(V1/T1) = V2

417.15 K(6.2 L/296.45 K) = 8.7 L

Remember to almost always change celcius to kelvin. Also, this is part of Charle's Law (temp and volume are proportional, so if temp increaces so must the volume or vice versa). Lastly, Charle's Law has the formula of V1/T1 = V2/T2. I just rearranged it to go along with your problem. Hence, the T2(V1/T1) = V2

4 0
4 years ago
The process of generating electricity from dams and nuclear power plants is very different, but some of the energy transformatio
Sindrei [870]

Answer:

yuh

Explanation:

hi i just wanted to say i love ur pfp

3 0
3 years ago
Please help! Thanks :D
Digiron [165]
<h3>1</h3>

Species shown in bold are precipitates.

  • Ca(NO₃)₂ + 2 KOH → Ca(OH)₂ + 2 KNO₃
  • Ca(NO₃)₂ + Na₂C₂O₄ → CaC₂O₄ + 2 NaNO₃
  • Cu(NO₃)₂ + 2 KI → CuI₂ + 2 KI
  • Cu(NO₃)₂ + 2 KOH → Cu(OH)₂ + 2 KNO₃
  • Cu(NO₃)₂ + Na₂C₂O₄ → CuC₂O₄ + 2 NaNO₃
  • Ni(NO₃)₂ + 2 KOH → Ni(OH)₂ + 2 KNO₃
  • Ni(NO₃)₂ + Na₂C₂O₄ → NiC₂O₄ + 2 NaNO₃
  • Zn(NO₃)₂ + 2 KOH → Zn(OH)₂ + 2 KNO₃
  • Zn(NO₃)₂ + Na₂C₂O₄ → ZnC₂O₄ + 2 NaNO₃

<h3>2</h3>

A double replacement reaction takes place only if it reduces in the concentration of ions in the solution. For example, the reaction between Ca(NO₃)₂ and KOH produces Ca(OH)₂. Ca(OH)₂ barely dissolves. The reaction has removed Ca²⁺ and OH⁻ ions from the solution.

Some of the reactions lead to neither precipitates nor gases. They will not take place since they are not energetically favored.


<h3>3</h3>

Compare the first and last row:

Both Ca(NO₃)₂ and Zn(NO₃)₂ react with KOH. However, between the two precipitates formed, Ca(OH)₂ is more soluble than Zn(OH)₂.

As a result, add the same amount of KOH to two Ca(NO₃)₂ and Zn(NO₃)₂ of equal concentration. The solution that end up with more precipitate shall belong to Zn(NO₃)₂.


<h3>4</h3>

Compare the second and third row:

Cu(NO₃)₂ reacts with KI, but Ni(NO₃)₂ does not. Thus, add equal amount of KI to the two unknowns. The solution that forms precipitate shall belong to Cu(NO₃)₂.

8 0
3 years ago
What is the percentage by mass of sulphur in Al2(SO4)3[A12SO4 =<br>342g/mol, S = 32]​
valentinak56 [21]

Answer: The percentage by mass of sulphur in Al_2(SO_4)_3 is 9.36%

Explanation:

Mass percent of an element is the ratio of mass of that element by the total mass expressed in terms of percentage.

{\text {Mass percentage}}=\frac{\text {mass of sulphur}}{\text {Total mass}}\times 100\%

Given: mass of sulphur = 32 g/mol

mass of Al_2(SO_4)_3 = 342 g/mol

Putting in the values we get:

{\text {Mass percentage}}=\frac{32g/mol}{342g/mol}\times 100\%=9.36\%

The percentage by mass of sulphur in Al_2(SO_4)_3 is 9.36%

4 0
3 years ago
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