Answer:
the time required for one half of a sample of a radioisotope to decay
Answer: The vapor pressure of water at 298 K is 3.565kPa.
Explanation:
The vapor pressure is determined by Clausius Clapeyron equation:

where,
= initial pressure at 298 K = ?
= final pressure at 373 K = 101.3 kPa
= enthalpy of vaporisation = 41.1 kJ/mol = 41100 J/mol
R = gas constant = 8.314 J/mole.K
= initial temperature = 298 K
= final temperature = 373 K
Now put all the given values in this formula, we get
![\log (\frac{101.3}{P_1})=\frac{41100}{2.303\times 8.314J/mole.K}[\frac{1}{298K}-\frac{1}{373K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7B101.3%7D%7BP_1%7D%29%3D%5Cfrac%7B41100%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B298K%7D-%5Cfrac%7B1%7D%7B373K%7D%5D)


Therefore, the vapor pressure of water at 298 K is 3.565kPa.
Answer:
<u>heptan-2-one</u>
Explanation:
In this case, the final product would be a ketone: <u>heptan-2-one</u>. To understand why this molecule is produced we have to check the<u> reaction mechanism</u>.
The first step is the <u>protonation</u> of the triple bond to produce the more stable carbocation (a secondary one) by the action of sulfuric acid
. The next step is the <u>attack of water</u> to the carbocation to produce a new bond between C and the O, producing a positive charge in the oxygen. Then, a <u>deprotonation</u> step takes place to produce an <u>enol</u>. Finally, we will have a rearrangement (<u>keto-enol tautomerism</u>) to produce the final ketone.
See figure 1
I hope it helps!