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Solnce55 [7]
4 years ago
5

Describe the nucleus of the atom. Include a description of its size relative to the rest of the atom.

Chemistry
1 answer:
faust18 [17]4 years ago
6 0

Answer:

The nucleus is the most densely compacted part of the atom, it is in the center circled by the electron cloud or shells. It is filled with positively charged protons, and neutrons which have no charge. It is smaller than the electron cloud in size, but in quantity it has more subatomic particles since protons and electrons are equal and the nucleus has nuetrons

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Which group is in the leftmost column on the periodic table?
Gelneren [198K]
Answer: alkali metals
8 0
3 years ago
How many grams of copper (II) fluoride, CuF2, are needed to make 5.1 liters of a 1.4M solution?
Alexus [3.1K]

Answer: 724.71 grams

Explanation:

Volume of solution (v) = 5.1 liters

Concentration of solution (c) = 1.4M

Amount of CuF2 needed (n) = ?

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

make n the subject formula

n = c x v

n = 1.4M x 5.1 Liters

n = 7.14 moles

Since, 7.14 moles of CuF2 (n) is needed, use the molar mass of CuF2 to get the mass in grams.

The atomic masses of Copper = 63.5g;

and Fluorine = 19g

So, I CuF2 = 63.5g + (19g x 2)

= 63.5g + 38g

= 101.5g/mol

Then, apply the formula

Number of moles = mass in grams / molar mass

7.14 moles = m / 101.5 g/mol

m = 7.14 moles x 101.5 g/mol

m = 724.71g

Thus, 724.71 grams of copper (II) fluoride, CuF2, are needed to make 5.1 liters of a 1.4M solution

7 0
4 years ago
Help me!<br>I need some quick answers pls​
Nana76 [90]

Explanation:

please mark me as brainlest and follow me

8 0
3 years ago
The pH of 0.50 M benzoic acid is 2.24. Calculate the change in pH when 2.64 g of C6H5COONa is added to 38 mL of 0.50 M benzoic a
meriva

Answer:

1.93

Explanation:

Moles of C_{6}H_{5}COOH = 38/1000 × 0.50 = 0.019mol

Moles of C_{6}H_{5}COONa = Mass/Molar mass = 2.64/144.10 = 0.018321mol

Final pH = pKa + log([C_{6}H_{5}COONa]/[C_{6}H_{5}COOH]

= -log Ka  + log(mols of C_{6}H_{5}COONa]/mols of C_{6}H_{5}COOH

= -log(6.5 × 10^(-5)) + log (0.018321/0.019)=4.17

change in pH = final - initial pH

= 4.17 - 2.24

=1.93

5 0
4 years ago
List the following elements from increasing electronegativity: boron, magnesium, calcium, chlorine, argon
pishuonlain [190]

Answer:

The list of elements from increasing electronegativity: Calcium <  magnesium < chlorine < argon < boron.

Explanation:

In the periodic table if you move from left to right there would be an increase in the electronegativity of the elements. If you move from the bottom to the top of the groups in the periodic table the electronegativity increases and if u move to the bottom from down its decreases.

Calcium is in the 2nd group below magnesium so calcium is the least electronegative among given elements then magnesium and then chlorine as it is top of magnesium then argon, as it is right to the chlorine, and boron has the most electronegativity as it is above rest of the elements.

6 0
3 years ago
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