A. 1/5 fish
We know that 2/5 of Mike's fish are clownfish. Therefore, 3/5 are not clownish as 5/5 – 2/5 = 3/5. Also, if you look at the model, there are five pieces. If we assume that model represents the whole of Mike's fish and you take away two pieces, you are left with 3/5. So we know that the remaining fish is 3/5
Next, we know that of these 3/5 fish, 1/3 is damselfish, so we need to find 1/3 of 3/5. To do this, we must multiply 1/3 by 3/5 as "of" means multiply in Math.
So: 1/3 • 3/5 = 1 • 3/3 • 5 = 3/15 3 ÷ 3 = 1 and 15 ÷ 3 = 5 3/15 = 1/5
1/5 of Mike's fish are damsel fish
B. 2/5 fish
Now we know that 1/5 of Mike's fish is damselfish, and 2/5 is clownfish. To find the fraction of his fish that are neither, therefore, we must subtract their sum from the whole.
First, we add 1/5 and 2/5 together. Adding the numerators, 1 and 2, we get 1/5 + 2/5 = 3/5
Next, we subtract: 5/5 – 3/5 = 2/5, so 2/5 of his fish are neither clownfish or damselfish
And if you look at the model again, you can see that if you cross out 1 piece for the damselfish, and 2 pieces for the clownfish, you are left with 2/5
Answer:
22
Step-by-step explanation:
ST is y and SU is 2y-4.
Note that SU = ST + TU = y + 18
So we have 2y - 4 = y + 18
2y - 4 = y + 18
2y = y + 22
y = 22
So ST is 22.
:)
Answer:
x = -3/14
Step-by-step explanation:
1/2(2x-1) = -1/7 -4/7
Combine like terms
1/2(2x-1) = -5/7
Multiply each side by 2
2*1/2(2x-1) = -5/7*2
2x-1 = -10/7
Add 1 to each side
2x-1+1 = -10/7 +1
2x = -10/7 +7/7
2x = -3/7
Divide by 2
2x/2 = -3/7 *1/2
x = -3/14
Polar form: (r,θ)
Using these formulas:
x²+y²=r²
tan(θ)=y/x
We have the point (1,1) in cartesian coordinates. We need to find r and θ to get it in polar form.
r²=1²+1²
r²=2
r=±√2
tan(θ)=1/1
tan(θ)=1
θ=π/4 radians or 45 degrees
Polar coordinates: (√2,π/4)
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Edward sliced 6 chocolate cakes and 12 lemon cakes
