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2 years ago

What is the area of this triangle? base = 5 mm Height = 6mm

Mathematics

2 answers:

garri49 [273]2 years ago

6 0

The area is 15 mm squared

1/2 times 5 times 6
The formula is 1/2 times base times height or base times height/2

hichkok12 [17]2 years ago

5 0

Area of a triangle can be found using the equation base x height / 2

(5)(6)/2 = 30/2 = 15

The area of the triangle is 15mm

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The following are the last 10 run scores Colin got in cricket:

Solnce55 [7]

Answers:

a) Mean = 20.4
b) New mean = 20

==================================================

Explanation:

To get the mean, we add up the scores and divide by 10 (because there are 10 scores at first)

28+13+4+12+32+22+13+22+26+32 = 204

204/10 = 20.4

The mean is 20.4

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For part b), we redo those steps shown above, but tack 16 onto the list. So we'll add up all the values (including that 16 at the end) and divide by 11 this time.

28+13+4+12+32+22+13+22+26+32+16 = 220

220/11 = 20

The new mean is 20.

The new mean is slightly smaller than the old mean. Notice how 16 is smaller than 20.4, so this new score pulls down the mean just a little bit.

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2 years ago

What is the median of the following data set?

AysviL [449]

Answer:

0 is the answer

Step-by-step explanation:

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2 years ago

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Someone please help me with this lol… have no idea what I’m doing

Sholpan [36]

Given:

$\cos \theta =\dfrac{3}{5}$

$\sin \theta$

To find:

The quadrant of the terminal side of $\theta$ and find the value of $\sin\theta$ .

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

$\cos \theta =\dfrac{3}{5}$

$\sin \theta$

Here cos is positive and sine is negative. So, $\theta$ must be lies in Quadrant IV.

We know that,

$\sin^2\theta +\cos^2\theta =1$

$\sin^2\theta=1-\cos^2\theta$

$\sin \theta=\pm \sqrt{1-\cos^2\theta}$

It is only negative because $\theta$ lies in Quadrant IV. So,

$\sin \theta=-\sqrt{1-\cos^2\theta}$

After substituting $\cos \theta =\dfrac{3}{5}$ , we get

$\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}$

$\sin \theta=-\sqrt{1-\dfrac{9}{25}}$

$\sin \theta=-\sqrt{\dfrac{25-9}{25}}$

$\sin \theta=-\sqrt{\dfrac{16}{25}}$

$\sin \theta=-\dfrac{4}{5}$

Therefore, the correct option is B.

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2 years ago

Which equation represents the graphed function?

scoundrel [369]

Solution:

we have been asked to find

Which equation represents the graphed function?

As we can see in the graph, the line is passing through the point (2,0) and (0,-3).

As we know the equation of the passing through two points is given by the formula

$(y-y_1)=m(x-x_1)\\
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So the equation of the line will be

$y-0=\frac{3}{2}(x-2)\\
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y= \frac{3}{2}x-3\\
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Serga [27]

( 2a2 - 2b - 1 ) Is the answer when simplifying the expression.

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2 years ago

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