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FrozenT [24]
3 years ago
10

If the discrminant of a quadratic equation is 4, which statement describes the roots

Mathematics
1 answer:
ryzh [129]3 years ago
4 0

<em>Hi ^^</em>

<u>Note: This answer is already on brainly, but to save up your time here is the answer (the owner of the answer is listed below).</u>

<em>Owner:  timothycarney2004</em>

<em>Rank: Ambitious</em>

--------------------------------------------------------------------------------------------------------------

<u>Answer:</u><em> There are </em><u>two </u><em>real roots </em>

<em> </em><u>Step-by-step explanation:</u><em> Terms in this set (6) If the discriminant of a quadratic equation is 4, which statement describes the roots? B. There are two real roots.</em>

<em>--------------------------------------------------------------------------------------------------------------</em>

<em />

Anyways bye! <3

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Five less than twice a number is seven
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Answer:

2x - 5 = 7

2x -5 + 5 = 7 + 5

2x = 12

2/2x = 12/2

x = 6

Step-by-step explanation:

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A right rectangular prism is shown. The base rectangle has side lengths of 10 centimeters and 3 centimeters. The height of the p
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Determine the number of possible outcomes when tossing one coin ,two coins ,and three coins then determine the number of possibl
m_a_m_a [10]

Number of possible outcome for tossing N coins = 2^N

Solution:

Possible outcomes when tossing one coin = {H, T}

Number of possible outcomes when tossing one coin = 2 =2^1

Possible outcomes when tossing two coins = {HH, HT, TH, TT}

Number of possible outcomes when tossing two coins = 4 =2^2

Possible outcomes when tossing three coins

                                 = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}

Number of possible outcomes when tossing three coins = 8 =2^3

Therefore, the sequence obtained is 2^1, 2^2, 2^3.

If continue this sequence, we can obtain number of possible outcome for tossing N coins is 2^N.

7 0
3 years ago
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Answer:

18r-4

Step-by-step explanation:

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Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.
Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{1599\text{ years}}

k=4.33\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 1000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=5.19g

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 10000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=0.105g

Thus, the amount after 10000 years will be, 0.105 grams.

4 0
4 years ago
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