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SIZIF [17.4K]
4 years ago
7

Jackie had $135 to spend at the mall. She spent 29% of that money on a dress. Jackie spent $___ on the dress. (Make sure to ente

r the answer as a decimal number only. Do not enter special characters such as the dollar symbol.)
Mathematics
2 answers:
antoniya [11.8K]4 years ago
5 0
Your Answer is 39.15
olganol [36]4 years ago
5 0

Answer:  39.15

Step-by-step explanation:

29% = 29/100 = .29

$135.00 x .29 = $39.15

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If someone is making a circular garden wall that has a diameter of 100, what’s the circumstance?
mylen [45]

If the diameter is 100  

The radios is 50 so using the formula

C=2π r

the circumferences is:

314.159


8 0
3 years ago
NEED HELP PLS NEED HELP PLS I DONT WANNA FAIL PLS HELP HELP HELP
bagirrra123 [75]

Answer:

\huge\boxed{\sf 126\° \ OR \ 145 \°}

Step-by-step explanation:

m∠4 + m∠7 = 180    (Adjacent Angles of a parallelogram)

<u>Given that</u> m∠4 = x + 45, m∠7 = x² + 45

x + 45 + x² + 45 = 180

x² + x + 90 = 180

x² + x = 180 - 90

x² + x = 90

x² + x - 90 = 0

Using mid-term break formula

x² + 10x - 9x - 90 = 0

x(x+10) - 9(x+10) = 0

(x - 9)(x + 10) = 0

<u>Either, </u>

x-9 = 0       <u>OR</u>      x+10 = 0

x = 9          <u>OR</u>        x = -10

\rule[225]{225}{2}

Now,

m < 7 = x² + 45

<u>For x = 9</u>

m < 7 = (9)² + 45

m < 7 = 81 + 45

<h3>m < 7 = 126°</h3>

<u>For x = -10</u>

m < 7 = (-10)² + 45

m < 7 = 100 + 45

<h3>m < 7 = 145°</h3>

\rule[225]{225}{2}

Hope this helped!

<h3>~AnonymousHelper1807</h3>
4 0
3 years ago
Ep-8 if grounded aboard a small powerboat, which is a method to help free yourself?
andreyandreev [35.5K]
<span>Grounding on boats is something like a mystery to most of the people. They think that the factory hooked it up like that and therefore the installation must be correct. But that's something which will not work every time.</span>
Thus if you are grounded aboard a small powerboat then place everybody aboard in the center of the boat and<span> t</span>ry to kedge your boat off the obstruction. 

5 0
3 years ago
Will mark branliest answer if gotten right!!!!!
Crank

Answer:

it is 4

Step-by-step explanation:

i will do this some other time

7 0
3 years ago
If sin theta = 2/5 and theta is in quadrant I, determine the following.
anzhelika [568]

\bf sin(\theta )=\cfrac{\stackrel{opposite}{2}}{\stackrel{hypotenuse}{5}}\impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a \qquad \begin{cases} c=\stackrel{hypotenuse}{5}\\ a=adjacent\\ b=\stackrel{opposite}{2}\\ \end{cases} \\\\\\ \pm\sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a\implies \stackrel{I~Quadrant}{+\sqrt{21}=a}


recall that cosine is positive on the I Quadrant, so though we get a ± valid roots, only the positive one applies.


\bf cos(\theta)=\cfrac{\stackrel{adjacent}{\sqrt{21}}}{\stackrel{hypotenuse}{5}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{2}}{\stackrel{adjacent}{\sqrt{21}}} \qquad \qquad cot(\theta)=\cfrac{\stackrel{adjacent}{\sqrt{21}}}{\stackrel{opposite}{2}} \\\\\\ csc(\theta)=\cfrac{\stackrel{hypotenuse}{5}}{\stackrel{opposite}{2}} \qquad \qquad sec(\theta)=\cfrac{\stackrel{hypotenuse}{5}}{\stackrel{adjacent}{\sqrt{21}}}


now, for tangent and secant, let's rationalize the denominator.


\bf tan(\theta)\implies \cfrac{\stackrel{opposite}{2}}{\stackrel{adjacent}{\sqrt{21}}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{21} \\\\\\ sec(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\stackrel{adjacent}{\sqrt{21}}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{5\sqrt{21}}{21}

5 0
3 years ago
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