Question

It took Mark 6 hours to drive from his college to his home. The next week he drove the same distance from his home back to his college in 5 hours. If the average rate for his first trip was r miles per hour, what was the average rate for the second trip, in terms of r ?

Answer 1

We need to use the following formula of distance .

Distance= speed * time .

For the first time

distance = 6r

And let the average rate for the second time be s

So distance = 5s

Since distance remains same, so we get

6r=5s

Now we have to solve for s. And for that we need to get rid of 5, by dividing both sides by 5, that is

$s =\frac{6r}{5}$

And that's the required average rate for the second trip .