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4 years ago

12

Sue bought a picnic table on sale for 50% off the original price. The store charged her 10% tax and her final cost was $22.00. W

hat was the original price of the picnic table?

1 answer:

timama [110]4 years ago

8 0

Answer:

40

Step-by-step explanation:

Final cost is 22, which is 110% of the price., which makes final cost to be 22/1.1=20

The original price 20/0.5=40

You might be interested in

OlgaM077 [116]

First, we're going to see the candies per minute that machine C packs.
150 / 2 = 75

Now that we know that machine C packs 75 candies per minute, we're going to multiply the candies machine C makes by 11 minutes.
75 x 11 = 825

We're now gonna do the same with machine D.
130 x 11 = 1430

Then we're going to find the difference between machine C and machine D, we do this because the question basically asks how much more candies can machine D pack than machine C.
1430 - 825 = 605 candies.

This is how we find our final answer.

Our answer would be D) 605.

Hope this helps!~

4 0

3 years ago

The number of fives is 3 more than six times the number of tens. Let t represent the number of tens. Write an expression for the

bixtya [17]

Answer:

The required expression is f = 3+6t

Step-by-step explanation:

Let t represent number of tens

Let f represent number of fives

So, the expression for number of fives can be formed by using:

The number of fives is 3 more than six times the number of tens.

f = 3+6t

So, the required expression is f = 3+6t

4 0

3 years ago

If D is midpoint of side BC of triangle ABC. P and Q are points lying respectively on side AB and AC such that DP is parallel to

LUCKY_DIMON [66]

See proof below

Step-by-step explanation:

Assume triangle ABC to have vertices at;

A(2,-1), B(2,-7) and C(6,-7)

D is midpoint of BC, thus D is at (4,-7)

The P and Q, are lying on side AB and AC, hence assume P is at (2,-4) and Q is at (4,-4) such at DP is parallel to QA

Plot the points on a graph tool and join the points to view the sketch.

To prove area of triangle CPQ is 1/4 area of ABC will be;

Find area ABC and CPQ then compare the areas.

Apply the distance formula to find the length of sides of the triangles then find the areas.

The distance formula is;

$d=\sqrt{x_2-x_1)^2+(y_2-y_1)^2}$

Length of side AB from the sketch is;

$AB=\sqrt{(2-2)^2+(-7--1)^2} =\sqrt{-6^2} =\sqrt{36} =6units$

Length of side BC will be;

$BC=\sqrt{(-7--7)^2+(6-2)^2} =\sqrt{4^2} =\sqrt{16} =4units$

Thus area of triangle ABC will be;

1/2 *base length*height ------because it is a right-triangle

1/2*4*6=12 square units

Find the lengths of all sides of triangle CPQ

Length of side PQ is half that of side BC thus PQ=2 units

Length of side PC is;

$PC=\sqrt{(6-2)^2+(-7--4)^2} =\sqrt{4^2+-3^2} =\sqrt{16+9} =\sqrt{25} =5units$

Length of side QC will be;

$QC=\sqrt{(6-4)^2+(-7--4)^2} =\sqrt{2^2+-3^3} =\sqrt{4+9} =\sqrt{13}$

QC= √13 = 3.6 units

Find area of triangle CPQ given all sides by applying the Heron's formula for area of triangle which is;

A=√s(s-a)(s-b)(s-c) where;

A=area of the triangle

s= half the perimeter of the triangle

a=side PQ = 2 units

b=side PC = 5 units

c= side QC = 3.6 units

Finding the perimeter of triangle CPQ will be;

P=sum of all sides

P=2+5+3.6 =10.6 units

s=10.6/2 = 5.3

Area of the triangle CPQ will be;

$A=\sqrt{5.3(5.3-2)(5.3-5)(5.3-3.6)} \\A=\sqrt{5.3(3.3)(0.3)(1.7)} \\A=\sqrt{8.9} =2.98$

A=3.0 (1 decimal place)

Compare the areas;

Area of triangle ABC=12 square units

Area of triangle CPQ = 3 square units

Area of triangle CPQ / Area of triangle ABC = 3/12 =1/4

Thus you have proved that area of triangle CPQ is 1/4 th area of triangle ABC because 1/4 *12 =3

Learn More

Area of a triangle ;brainly.com/question/14869984

The Heron's formula : brainly.com/question/10713495

Keywords: midpoint, triangle, sides, parallel, prove , area, equal

#LearnwithBrainly

6 0

3 years ago

luda_lava [24]

Let R be the greater radius and r be the smaller radius

A) Area of the sidewalk = R^2 - r^2 - This can be the expression

B) = 3.14
=(R^2-r^2)
=(11^2-9^2)
=(121-81)
=*40

That was the simplified expression

Answer = 3.14 * 40 = 125.6m^2

8 0

3 years ago

Luis has a pyramid shaped plant pot. It has a square base with a side length of 36 cm, and the height of the pot is 36 cm. Luis

umka21 [38]

Answer:

The required volume, if he wants to fill 75% of the pot's volume, is 11664cm³

Step-by-step explanation:

The volume of a pyramid is given as

$V = \frac{1}{3} \times A \times h$

Where V is the pot's volume, A is the base area and h is the height.

Our base is a square, so the base area, if s denotes the side length, would be s x s.

s = 36cm, therefore we have A = 36cm X 36cm = 1296cm².

The height is given as 36cm, therefore we have our volume to be:

$V = \frac{1}{3} \times 1296cm^2 \times 36cm$

$V = 15552cm^3$

Since Luis wants to fill 75% of the pot's volume with soil. Then it will take

$\frac{75}{100} \times 15552cm^3 = 11664cm^3$

Thus, the required volume, if he wants to fill 75% of the pot's volume, is 11664cm³

7 0

3 years ago