Let 2x – y = 3 ——— equation 1
Let x + 5y = 14 ——— equation 2
Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3
• Put eqn 3 in eqn 2
(y + 3 / 2) + 5y = 14
6y = 14 – 3/2
6y = 25/2
y = 25/12
• put y = 25/12 in eqn 3
x = (25/12 + 3/2)
x = 43/12
Because the radius is properly the same or the volume is the same
Answer:
m<NQS = 32°
Step-by-step explanation:
Given:
m<BQS = 80°
m<BQN = 48°
Required:
m<NQS
SOLUTION:
Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.
Therefore:
m<BQN + m<NQS = m<BQS (angle addition postulate)
48° + m<NQS = 80° (substitution)
m<NQS = 80 - 48° (Subtraction of 48 from each side)
m<NQS = 32°
Answer:
The correct options are:
x= -1.1
x= 2.4
x = 6
Step-by-step explanation:
The roots of any polynomial can easily be determined by the graph. To find the roots from the graph, we just have to see the values of x, for which the value of whole polynomial becomes 0.
We can see in the graph that there are three points where the value of polynomial becomes 0. that are
At x= -1.1
At x= 2.4
At x = 6
Thus, these are the roots
Answer:
the answer would be 9 I think
