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kumpel [21]
3 years ago
15

Write an equation of the line that passes through the points. (0,-2) (4,-2)

Mathematics
2 answers:
AVprozaik [17]3 years ago
5 0

y = -2

Since this is a line, it will be a straight linear line passing. Since it passes through coordinates with same y value, there is no slope.

romanna [79]3 years ago
3 0

Answer:

y = -2

Since this is a line, it will be a straight linear line passing. Since it passes through coordinates with same y value, there is no slope.

Step-by-step explanation:

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Factor and\or expand the following expression : 3(2x + w)
lutik1710 [3]

Answer:

6x +3w

Step-by-step explanation:

3(2x + w)

Distribute

3*2x +3*w

6x +3w

7 0
3 years ago
Read 2 more answers
Cost A=0.6489<br><br> take the inverse cosine of both sides
Stolb23 [73]
I am not quite sure what the question asks for,
But this is what i assume it wants:

Cos A= 0.6489
In this given one, we basically find the size of the angle A
we do cosine inverse on both sides to get the size of the angle A
cos^{-1} : It looks like this in the calculator
cos^{-1} × cos A=cos^{-1}(0.6489)
(cos^{-1} and cos cancels out)
A=cos^{-1}(0.6489)
A=49.54°
check: 
cos 49.54=0.6489 (its right!)

6 0
3 years ago
Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ
Nata [24]

Answer: 5x-3y=44

Step-by-step explanation:

We know that , the equation of a line that passes through (a,b) and (c,d) is given by :_

(y-b)=\dfrac{d-b}{c-a}(x-a)

Standard form of equation of line = Ax+By=C

Given points =  (7, -3) and (4, -8)

Then, the equation of a line that passes through the points . (7, -3) and (4, -8) is given by -

(y-(-3))=\dfrac{-8-(-3)}{4-7}(x-7)

(y+3)=\dfrac{-8+3}{-3}(x-7)   [∵ (-)(-)=(+)]

(y+3)=\dfrac{-5}{-3}(x-7)

(y+3)=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

9+35=5x-3y

44=5x-3y

Or 5x-3y=44

Hence, the required equation :-5x-3y=44

4 0
3 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
Read 2 more answers
Please help and tell me why you got that answer, will mark brainliest
Georgia [21]

Answer:

The answer is G.

Step-by-step explanation:

When comparing G with the other 3 options, ONLY G hasn't ran more than 6 miles; the rest all options show that he ran more miles in few minutes.

5 0
2 years ago
Read 2 more answers
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