What's the answer to -6<21

Work out 3/5 of 900

Mars2501 [29]

Answer:

540

Step-by-step explanation:

1. We assume, that the number 900 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 900 is 100%, so we can write it down as 900=100%.

4. We know, that x is 3.5% of the output value, so we can write it down as x=3.5%.

5. Now we have two simple equations:

1) 900=100%

2) x=3.5%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

900/x=100%/3.5%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 3.5% of 900

900/x=100/3.5

(900/x)*x=(100/3.5)*x - we multiply both sides of the equation by x

900=28.571428571429*x - we divide both sides of the equation by (28.571428571429) to get x

900/28.571428571429=x

31.5=x

x=31.5

now we have:

3.5% of 900=31.5

3 0

3 years ago

How much would $200 invested at 7% interest compounded annually be

raketka [301]

<h3>Answer: Choice A. $280.51</h3>

Work Shown:

A = P*(1+r/n)^(n*t) .... compound interest formula

A = 200(1+0.07/1)^(1*5) .... plug in given info

A = 200*(1.07)^5

A = 200*1.4025517307

A = 280.51034614

A = 280.51

3 0

3 years ago

There are two spinners. Each spinner has 10 equal sectors labeled with the numbers 1 through 10.

Reika [66]

Answer: Second option is correct.

Step-by-step explanation:

Since we have two spinners,

Each spinner has 10 equal sectors labeled with the numbers from 1 to 10.

Primes numbers from 1 to 10 is given by

$\{2,3,5,7\}$

So, number of outcomes shows a primes number from 1 to 10 = 4

Similarly ,

Composite numbers from 1 to 10 is given by

$\{4,6,8,9,10\}$

So, number of outcomes shows a composite number from 1 to 10 =5

∴ Total outcomes show a prime number on the first spinner and a composite number on the second spinner is given by

$4\times 5=20\\$

Thus, Second option is correct.

3 0

3 years ago

I need help with Q9 c, I’ve done a and b if it helps, b=325 but I am just stuck on question 9C, I know the answer is 500N (as it

777dan777 [17]

Step-by-step explanation:

I know you've already done parts a and b, but I'll show the work for that before I do c.

Draw two free body diagrams, one for the car and one for the trailer. The car pulls the trailer forward with a tension force T, so the trailer pulls backward on the car with an equal and opposite force T.

The car also has a 1200 N forward force from the engine, and a 200 N backwards force from resistance.

The trailer has a backwards resistance force of 100 N.

Sum of forces on the car:

∑F = ma

1200 − 200 − T = 900a

1000 − T = 900a

Sum of forces on the trailer:

∑F = ma

T − 100 = 300a

To solve the system of equations, first add the equations together.

1000 − 100 = 1200a

900 = 1200a

a = 0.75 m/s²

Plug back into either equation to find the tension force:

T = 325 N

Now for part c, draw new free body diagrams for the car and trailer. This time, the car is pushing back on the trailer to slow it down. So the trailer is pushing forward on the car with an equal and opposite force. The magnitude of that tension force is given to be 100 N.

The car also has a backwards 200 N force from resistance, and a backwards brake force F.

The trailer has a backwards 100 N force from resistance.

Sum of forces on the car:

∑F = ma

100 − 200 − F = 900a

-100 − F = 900a

Sum of forces on the trailer:

∑F = ma

-100 − 100 = 300a

-200 = 300a

a = -⅔

Plugging into the first equation:

-100 − F = 900 (-⅔)

-100 − F = -600

F = 500 N

4 0

3 years ago

Let f(x) = 5x + 12. Find f−1(x).

Brilliant_brown [7]

It would be the top one bro i know

4 0

3 years ago