Answer:
No, to be a function a relation must fulfill two requirements: existence and unicity.
Step-by-step explanation:
- Existence is a condition that establish that every element of te domain set must be related with some element in the range. Example: if the domain of the function is formed by the elements (1,2,3), and the range is formed by the elements (10,11), the condition is not respected if the element "3" for example, is not linked with 10 or 11 (the two elements of the range set).
- Unicity is a condition that establish that each element of the domain of a relation must be related with <u>only one</u> element of the range. Following the previous example, if the element "1" of the domain can be linked to both the elements of the range (10,11), the relation is not a function.
The answer is easy
So we need to fund m2NLM
The answer is c
You just solve for y.
y=<span><span><span>13/11</span>x</span>+<span>12/<span>11</span></span></span>
Answer:
Use cross product to determine if the two ratios form a proportion. Here we can see that 2/16 and 5/40 are proportions since their cross products are equal. Percent means hundredths or per hundred and is written with the symbol, %. Percent is a ratio were we compare numbers to 100 which means that 1% is 1/100.
Step-by-step explanation:
2. means that for every x, there is eactly one y
basically, we can use the vertical line test to see if it crosses at any 2 points
first one works
2nd one works
3rd works
4th works
5th works
they are all one to one functions
3.
easy
steps
for f(x)=?
replace f(x) with y
switch x and y
solve for y
replace y with f⁻¹(x)
so
![f(x)=(1+x)^3-2](https://tex.z-dn.net/?f=f%28x%29%3D%281%2Bx%29%5E3-2)
replace
![y=(1+x)^3-2](https://tex.z-dn.net/?f=y%3D%281%2Bx%29%5E3-2)
switch
![x=(1+y)^3-2](https://tex.z-dn.net/?f=x%3D%281%2By%29%5E3-2)
solve
![x+2=(1+y)^3](https://tex.z-dn.net/?f=x%2B2%3D%281%2By%29%5E3)
![\sqrt[3]{x+2}=1+y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B2%7D%3D1%2By)
![-1+\sqrt[3]{x+2}=](https://tex.z-dn.net/?f=-1%2B%5Csqrt%5B3%5D%7Bx%2B2%7D%3D)
replace
![f^{-1}(x)=-1+\sqrt[3]{x+2}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D-1%2B%5Csqrt%5B3%5D%7Bx%2B2%7D)
first option
4.
domain, hmm we can't divide by 0 so domain is all real numbers except for x=0
domain is
![(-\infty,0) \cup(0,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C0%29%20%5Ccup%280%2C%5Cinfty%29)
hmm, range
as x approaches negative or positive infinity, f(x)=5
as x approaches 0 from the left, f(x) appraoches negative infintiy
as x approaches 0 from the right , f(x) appraoches positive infintiy
so range is
![(-\infty,5) \cup(5,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C5%29%20%5Ccup%285%2C%5Cinfty%29)
domain is
![(-\infty,0) \cup(0,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C0%29%20%5Ccup%280%2C%5Cinfty%29)
range is
![(-\infty,5) \cup(5,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C5%29%20%5Ccup%285%2C%5Cinfty%29)
answer is the 4th option