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I am Lyosha [343]
3 years ago
13

When we talk about how a Ferrari obtains a top speed of 349 km/h, are we referring to average speed or instantaneous? How do you

know?
Physics
1 answer:
Viktor [21]3 years ago
4 0

Answer:

We are talking about instantaneous speed. This is because it says the Ferrari obtains a "Top speed" of 349 km/h. This means in one point of time, the Ferrari can reach 349 km/h. Hence, instantaneous speed.

Explanation:

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A 25-cm rod moves at 5. 0 m/s in a plane perpendicular to a magnetic field of strength 0. 25 t. the rod, velocity vector, and ma
Bad White [126]

Length L = 25 cm = 0.25 m,  B = 600 G =  0.06 T ( 1G = 0.0001 T)

emf= 10 V

Solution:

emf = vBL

v= emf / BL

5 = emf/ (0.25 T× 0.25 m)

emf = 0.3125 v

Magnetic field

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.

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5 0
2 years ago
A perpendicular force is applied to a certain area and produces a pressure P. If the
Furkat [3]

Answer:

p/2

Explanation:

4 0
3 years ago
Sound wave A delivers 2 J of energy in 2 s. Sound wave B delivers 10 J of energy in 5 s. Sound wave C delivers 2 mJ of energy in
Dmitry [639]

Answer:

In the order largest to smallest

Pc = Pb, Pa

Explanation:

Power = Energy expended/time

Pa = 2/2 = 1Watt

Pb = 10/5 = 2Watt

Pc = 2E-3/1E-3 = 2Watt

8 0
3 years ago
Two cylindrical containers are placed on a turntable. canister A is empty; canister B contains lead shots. each canister is the
devlian [24]

Answer:

c) both containers slide off the turntable at the same turntable speed.

Explanation:

The greater the mass of the cylinder, the greater the centrifugal force acting on it. That makes up for the greater force needed to move the heavier cylinder.

5 0
3 years ago
In a machine shop, a hydraulic lift is used to raise heavy equipment for repairs. The system has a small piston with a cross-sec
Mrac [35]

Answer:

F_s=1075.9493\ N

Explanation:

Given:

  • area of piston on the smaller side of hydraulic lift, a_s=0.075\ m^2
  • area of piston on the larger side of hydraulic lift, a_l=0.237\ m^2
  • Weight of the engine on the larger side, W_l=3400\ N

Now, using Pascal's law which state that the pressure change in at any point in a confined continuum of an incompressible fluid is transmitted throughout the fluid at its each point.

P_s=P_l

\frac{F_s}{a_s}=\frac{W_l}{a_l}

\frac{F_s}{0.075} =\frac{3400}{0.237}

F_s=1075.9493\ N is the required effort force.

5 0
4 years ago
Read 2 more answers
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