1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ahrayia [7]
2 years ago
9

A parallel plate capacitor is charged up by a battery. The battery is then disconnected, but the charge remains on the plates. T

he plates are then pulled apart. Explain whether each of the following quantities increases, decreases, or remains the same as the distance between the plates increases.
(a) The capacitance of the capacitor
(b) The potential difference between the plates
(c) The electric field between the plates
(d) The electric potential energy stored by the capacitor.
Physics
1 answer:
Mazyrski [523]2 years ago
3 0

Given a capacitor that is charge by a battery

So when the battery was disconnect, the charge remains on the capacitor

One plate will have positive charge

And the other will have a negative charge but of same magnitude

Now, the plates are pulled apart, so the distance between them was extended

a. The capacitance of the capacitor?

The capacitance of a capacitor is given as

C = εo•A/d

Where C is the capacitance

εo is permissivity, a constant

A is are of plate

d is the distance apart

From the formula we notice that

Capacitance is inversely proportional to distance, so this implies that as the distance is increase, the capacitance is reduce.

Capacitance Decreases

b. Potential difference?

The potential difference is given as

q = CV

V = q/C

Or V=Ed

Where E is electric field

So the potential difference is inversely proportional to the capacitance, so we know that the capacitance is reducing, then voltage will increase.

Or, using the second relations

V=Ed, voltage is directly proportional to distance, So, if the distance apart is increasing then, the voltage is increasing

Voltage is increasing

c. Electric field between plate.

The electric field is given as

E = kQ/r²

So the electric field is inversely proportional to the distance square, so as the distance is an increase, the electric field is decreased.

Electric field decreases

d. Electric potential energy?

U = ½CV², then, q = CV

Then, U = ½qV

The electric potential energy is directly proportional to the voltage and since the voltage is increasing due to increase in distance, then the electric potential energy increases.

You might be interested in
Why type of energy is present after a solar panel changes forms?
NNADVOKAT [17]

Explanation:

Solar technologies convert sunlight into electrical energy either through photovoltaic (PV) panels or through mirrors that concentrate solar radiation. This energy can be used to generate electricity or be stored in batteries or thermal storage.

8 0
2 years ago
Read 2 more answers
you start your bicycle ride at the top of a hill. you coast down the hill at a constant acceleration of 2.00 m/s^2. When you get
stiv31 [10]
198 meters I think, I could be wrong
6 0
3 years ago
All objects____ energy.<br><br> Eliminate <br><br> Conduct <br><br> Radiate <br><br> Insulate
Trava [24]

the answer is c. radiate

7 0
3 years ago
A light ray is incident from air into glass (ng = 1.52) then onto water (nw= 1.33). The wavelength of light in air (na= 1) is ai
gregori [183]
The answer is is b hope this helped
3 0
3 years ago
Refer to a long, straight wire carrying constant current I. What can be concluded about the magnitude of the magnetic field at d
sergij07 [2.7K]

Answer:

<em>"the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"</em>

Explanation:

The magnitude of the magnetic field from a long straight wire (A approximately a finite length of wire at least for close points around the wire.) decreases with distance from the wire. It does not follow the inverse square rule as is the electric field from a point charge. We can then say that<em> "the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"</em>

From the Biot-Savart rule,

B = μI/2πR

where B is the magnitude of the magnetic field

I is the current through the wire

μ is the permeability of free space or vacuum

R is the distance between the point and the wire, in this case is = a

5 0
2 years ago
Other questions:
  • The sun is going down and most of the land is dark but we still can see silhouettes and outlines of objects because some light i
    8·2 answers
  • To test the quality of water sources in her area, Shameka collects five samples from each water source and tests the quality of
    9·1 answer
  • At what distance must a star be to have its apparent magnitude equal to its absolute magnitude?
    15·1 answer
  • Which of the following components promote total health and prevent the beginning of diseases and problems associated with physic
    13·1 answer
  • How is earth outer layer different from a cracked hard-boiled egg?
    11·1 answer
  • Discuss the role of global ization in the development of SI unit​
    7·1 answer
  • When I throw a ball in the air at what point will it have the least kinetic energy
    10·2 answers
  • A truck travels 1430 m uphill along a road that makes a constant angle of 5.76◦ with the horizontal.
    15·1 answer
  • A car makes a trip due north for three-fourths of the time and due south one-fourth of the time. The average northward velocity
    13·1 answer
  • What kind of mixture is the gravel at the bottom of the fish tank?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!