Answer:
782.461 m
Explanation:
![v_{yo}=0](https://tex.z-dn.net/?f=v_%7Byo%7D%3D0)
X-direction | Y-direction
| ![y=y_{o}+v_{yo}t+\frac{1}{2} a_{y} t^2](https://tex.z-dn.net/?f=y%3Dy_%7Bo%7D%2Bv_%7Byo%7Dt%2B%5Cfrac%7B1%7D%7B2%7D%20a_%7By%7D%20t%5E2)
| ![0=300-\frac{1}{2}(9.8)t^2](https://tex.z-dn.net/?f=0%3D300-%5Cfrac%7B1%7D%7B2%7D%289.8%29t%5E2)
x= 782.461 m | ![-300=-4.9t^2](https://tex.z-dn.net/?f=-300%3D-4.9t%5E2)
| ![\sqrt{\frac{-300}{-4.9} } =\sqrt{t^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B-300%7D%7B-4.9%7D%20%7D%20%3D%5Csqrt%7Bt%5E2%7D)
| ![7.82461=t](https://tex.z-dn.net/?f=7.82461%3Dt)
Answer:
(507 nm)
Explanation:
First of all let's calculate the energy of the photon absorbed by the electron, This is given by
![E=hf](https://tex.z-dn.net/?f=E%3Dhf)
where
h is the Planck constant
is the frequency of the photon
Substituting,
![E=(6.63\cdot 10^{-34}Js)(8.88\cdot 10^{14}Hz)=5.89\cdot 10^{-19} J](https://tex.z-dn.net/?f=E%3D%286.63%5Ccdot%2010%5E%7B-34%7DJs%29%288.88%5Ccdot%2010%5E%7B14%7DHz%29%3D5.89%5Ccdot%2010%5E%7B-19%7D%20J)
The energy of the second photon, the one emitted when the electron drops to the intermediate energy level, is 2/3 of this energy:
![E'=\frac{2}{3}E=\frac{2}{3}(5.89\cdot 10^{-19} J)=3.92\cdot 10^{-19} J](https://tex.z-dn.net/?f=E%27%3D%5Cfrac%7B2%7D%7B3%7DE%3D%5Cfrac%7B2%7D%7B3%7D%285.89%5Ccdot%2010%5E%7B-19%7D%20J%29%3D3.92%5Ccdot%2010%5E%7B-19%7D%20J)
The relationship between the energy of the photon and its wavelength
is
![E=\frac{hc}{\lambda}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7Bhc%7D%7B%5Clambda%7D)
where c is the speed of light. Solving for
, we find the wavelength:
![\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{3.92\cdot 10^{-19} J}=5.07\cdot 10^{-7} m](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7Bhc%7D%7BE%7D%3D%5Cfrac%7B%286.63%5Ccdot%2010%5E%7B-34%7D%20Js%29%283%5Ccdot%2010%5E8%20m%2Fs%29%7D%7B3.92%5Ccdot%2010%5E%7B-19%7D%20J%7D%3D5.07%5Ccdot%2010%5E%7B-7%7D%20m)
Answer:
34 m/s
Explanation:
m = Mass of glider with person = 680 kg
v = Velocity of glider with person = 34 m/s
= Mass of glider without person = 680-60 kg
= Gliders speed just after the skydiver lets go
= Mass of person = 60 kg
= Velcotiy of person = 34 m/s
As the linear momentum of the system is conserved
![m_1v_1+m_2v_2=mv\\\Rightarrow v_1=\dfrac{mv-m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{680\times 34-60\times 34}{680-60}\\\Rightarrow v_1=34\ m/s](https://tex.z-dn.net/?f=m_1v_1%2Bm_2v_2%3Dmv%5C%5C%5CRightarrow%20v_1%3D%5Cdfrac%7Bmv-m_2v_2%7D%7Bm_1%7D%5C%5C%5CRightarrow%20v_1%3D%5Cdfrac%7B680%5Ctimes%2034-60%5Ctimes%2034%7D%7B680-60%7D%5C%5C%5CRightarrow%20v_1%3D34%5C%20m%2Fs)
The gliders speed just after the skydiver lets go is 34 m/s
Mass number
The total number of protons and neutrons in the nucleus of an atom.
It is B) Wavelength, because it measures the "length" between "waves", therefore, wavelength.