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BARSIC [14]
3 years ago
11

6. Sandy adds 3 sugar packets to her tea in order to make it sweeter. She stirs in the sugar and then takes a sip. She notices t

hat not all the sugar was dissolved. What type of solution did she make?
A. Saturated B.Unsaturated C.Supersaturated D.Mildly saturated
Physics
1 answer:
irina1246 [14]3 years ago
7 0

Answer:

C.Supersaturated

Explanation:

There are three types of solution:

<u>SATURATED SOLUTION</u>:

It is the solution that contains maximum amount of solute dissolved in a solution in normal conditions.  

<u>UNSATURATED SOLUTION</u>:

It is the solution that contains less than the maximum amount of solute dissolved in a solution in normal conditions. It has space for more solute to be dissolved in it.

<u>SUPERSATURATED SOLUTION:</u>

It contains more than the maximum amount of solute dissolved in it. Such a solution has no capacity to dissolve any more solute under any conditions.

Since the sugar is no more dissolving in the tea and has settled down. Therefore, the solution is:

<u>C.Supersaturated</u>

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3 years ago
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7. Un bloque de 700 N se encuentra sobre una viga uniforme de 200 N y 6 m de longitud. El bloque está a una distancia de 1 m del
GrogVix [38]

Answer:

 x =  0.176 m

Explanation:

For this exercise we will take the condition of rotational equilibrium, where the reference system is located on the far left and the wire on the far right. We assume that counterclockwise turns are positive.

Let's use trigonometry to decompose the tension

      sin 60 = T_{y} / T

      T_{y} = T sin 60

       cos 60 = Tₓ / T

      Tₓ = T cos 60

we apply the equation

       ∑ τ = 0

       -W L / 2 - w x + T_{y} L = 0

 

the length of the bar is L = 6m

           -Mg 6/2 - m g x + T sin 60 6 = 0

             x = (6 T sin 60 - 3 M g) / mg

let's calculate

let's use the maximum tension that resists the cable T = 900 N

             x = (6 900 sin 60 - 3 200 9.8) / (700 9.8)

             x = (4676 - 5880) / 6860

             x = - 0.176 m

Therefore the block can be up to 0.176m to keep the system in balance.

5 0
3 years ago
Suppose a 1300 kg car is traveling around a circular curve in a road at a constant
Scrat [10]

Answer:

F = 4212 N

Explanation:

Given that,

Mass of a car, m = 1300 kg

Speed of car on the road is 9 m/s

Radius of curve, r = 25 m

We need to find the magnitude of the unbalanced force that steers the car out of its natural straight-  line path. The force is called centripetal force. It can be given by :

F=\dfrac{mv^2}{r}\\\\F=\dfrac{1300\times 9^2}{25}\\\\F=4212\ N

So, the force has a magnitude of 4212 N

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2 years ago
If an equation is dimensionally correct is thar equation a right equation<br>​
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PLEASE HURRYY!!!!The diagram shows two balls released from a device at the same time. The ball on the left falls freely from res
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Answer:

i'm pretty sure its B but i may be wrong if you dont wanna take the chance wait for someone

Explanation:

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