Consider the given function and the given interval. f(x) = (x − 4)2, [3, 6]

Assuming all variables are positive, use properties of logarithms to write the expression as a sum or difference of logarithms o

schepotkina [342]

C) six times log base two of x times seven times log base two of y minus log base two of eight.

5 0

2 years ago

Jay had 6 times as much money as Kay. Then Jay gave Kay $33. Jay now has twice as much money as Kay. How much did they each star

timofeeve [1]

Answer:

Jay started with $148.5 and Kay with $24.75.

Step-by-step explanation:

With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:

J=6K, where

J is the money Jay had

K is the money Kay had

Also, you know that Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:

J-33=2(K+33)

Now, you can replace J=6K in this equation and solve for K:

6K-33=2K+66

6K-2K=66+33

4K=66

K=24.75

Then, you can replace the value of K in J=6K:

J=6*24.75

J=148.5

According to this, the answer is that Jay started with $148.5 and Kay with $24.75.

7 0

2 years ago

Please give me the right answer if the algebraic expression is 11 decreased by k is thirty-two. How to write it.

Free_Kalibri [48]

11 - k = 32
- k = 21
k = -21

8 0

3 years ago

Find the area of the triangle formed by the origin and the points of intersection of parabolas y=− 1/3 (x−1)^2+8 and y=x^2−2x−3.

Kobotan [32]

Answer:

The area of the triangle formed by origin, and the points (4,5) and (-2,5) will be 15 sq. units.

Step-by-step explanation:

The two parabolas are $y = - \frac{1}{3}(x - 1)^{2} + 8$ and y = x² - 2x - 3.

Now, solving those two equations we will get the points of intersection.

So, $- \frac{1}{3}(x - 1)^{2} + 8 = x^{2} - 2x - 3$

⇒ - (x - 1)² + 24 = 3x² - 6x - 9

⇒ -x² + 2x - 1 + 24 = 3x² - 6x - 9

⇒ 4x² - 8x - 32 = 0

⇒ x² - 2x - 8 = 0

⇒ x² - 4x + 2x - 8 = 0

⇒ (x - 4)(x + 2) = 0

So, x = 4 or - 2.

Now, for x = 4 , y = 4² - 2(4) - 3 = 5 and the point of intersection is (4,5).

Or, for x = - 2, y = (- 2)² - 2(- 2) - 3 = 5 and the point of intersection is (-2,5).

Now, points (4,5) and (-2,5) make a straight line parallel to the x-axis at a perpendicular distance of 5 units from origin and its length is (4 - (- 2)) = 6 units.

So, the area of the triangle formed by origin, and the points (4,5) and (-2,5) will be = 0.5 × 5 × 6 = 15 sq. units. (Answer)

8 0

2 years ago

Please help me to solve this sum<br>please gI've correct answer

disa [49]

This question requires creating a few equations and working through them step-by-step. Now, first let's give each of the shapes a variable: let's say that the blue shape is a, the orange shape is b and the green shape is c.

1. We can technically create six formulas for the magic square, with three for sum of the rows and three for the sum of the columns, however the smartest way to approach this is to observe whether there are any obvious answers that we can get.

We can see in row 2 that there are three of the same shape (a) that add to 57. This makes it very simple to calculate the value of the shape.

Since 3a = 57

a = 57/3 = 19

2. Now we need to find a row or column that includes a and one other shape; we could choose either column 2 or 3, so let's go with column 2. Remembering that the blue shape is a and the orange shape is b:

2a + b = 50

Now, given that a = 19:

2(19) + b = 50

38 + b = 50

b = 12

3. We can now take any of the rows or columns that include the third shape (c) since we already know the values of the other two shapes. Let's take column 1:

a + b + c = 38

19 + 12 + c = 38

31 + c = 38

c = 38 - 31

c = 7

Thus, the value of the blue shape is 19, the value of the orange shape is 12 and the value of the green shape is 7.

3 0

2 years ago