Answer:
0
Step-by-step explanation:
9^2 * (1/3)^2 -9
PEMDAS says powers first
81 * 1/9 -9
Then multiply
9 -9
Then subtract
0
The question is an illustration of bearing (i.e. angles) and distance (i.e. lengths)
The distance between both lighthouses is 5783.96 m
I've added an attachment that represents the scenario.
From the attachment, we have:
![\mathbf{\angle A = 180^o - 120^o\ 43'}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cangle%20A%20%3D%20180%5Eo%20-%20120%5Eo%5C%2043%27%7D)
Convert to degrees
![\mathbf{\angle A = 180^o - (120^o +\frac{43}{60}^o)}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cangle%20A%20%3D%20180%5Eo%20-%20%28120%5Eo%20%2B%5Cfrac%7B43%7D%7B60%7D%5Eo%29%7D)
![\mathbf{\angle A = 180^o - (120^o +0.717^o)}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cangle%20A%20%3D%20180%5Eo%20-%20%28120%5Eo%20%2B0.717%5Eo%29%7D)
![\mathbf{\angle A = 180^o - (120.717^o)}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cangle%20A%20%3D%20180%5Eo%20-%20%28120.717%5Eo%29%7D)
![\mathbf{\angle A = 59.283^o}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cangle%20A%20%3D%2059.283%5Eo%7D)
![\mathbf{\angle B = 39^o43'}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cangle%20B%20%3D%2039%5Eo43%27%7D)
Convert to degrees
![\mathbf{\angle B = 39^o + \frac{43}{60}^o}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cangle%20B%20%3D%2039%5Eo%20%2B%20%5Cfrac%7B43%7D%7B60%7D%5Eo%7D)
![\mathbf{\angle B = 39^o + 0.717^o}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cangle%20B%20%3D%2039%5Eo%20%2B%200.717%5Eo%7D)
![\mathbf{\angle B = 39.717^o}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cangle%20B%20%3D%2039.717%5Eo%7D)
So, the measure of angle S is:
---- Sum of angles in a triangle
![\mathbf{\angle S = 180 - 59.283 - 39.717}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cangle%20S%20%3D%20180%20-%2059.283%20-%2039.717%7D)
![\mathbf{\angle S = 81}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cangle%20S%20%3D%2081%7D)
The required distance is distance AB
This is calculated using the following sine formula:
![\mathbf{\frac{AB}{\sin(S)} = \frac{AS}{\sin(B)} }](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%7BAB%7D%7B%5Csin%28S%29%7D%20%3D%20%5Cfrac%7BAS%7D%7B%5Csin%28B%29%7D%20%7D)
Where:
![\mathbf{AS = 3742}](https://tex.z-dn.net/?f=%5Cmathbf%7BAS%20%3D%203742%7D)
So, we have:
![\mathbf{\frac{AB}{\sin(81)} = \frac{3742}{\sin(39.717)}}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%7BAB%7D%7B%5Csin%2881%29%7D%20%3D%20%5Cfrac%7B3742%7D%7B%5Csin%2839.717%29%7D%7D)
Make AB the subject
![\mathbf{AB= \frac{3742}{\sin(39.717)} \times \sin(81)}](https://tex.z-dn.net/?f=%5Cmathbf%7BAB%3D%20%5Cfrac%7B3742%7D%7B%5Csin%2839.717%29%7D%20%5Ctimes%20%5Csin%2881%29%7D)
![\mathbf{AB= 5783.96}](https://tex.z-dn.net/?f=%5Cmathbf%7BAB%3D%205783.96%7D)
Hence, the distance between both lighthouses is 5783.96 m
Read more about bearing and distance at:
brainly.com/question/19017345
Answer:
f
(
x
)
=
5
x
2
−
2
x
+
3
g
(
x
)
=
4
x
2
+
7
x
−
5
f
(
g
(
x
)
)
=
5
(
4
x
2
+
7
x
−
5
)
2
−
2
(
4
x
2
+
7
x
−
5
)
+
3
=
80
x
4
+
280
x
3
+
45
x
2
−
350
x
+
125
−
8
x
2
−
14
x
+
10
+
3
=
80
x
4
+
280
x
3
+
45
x
2
−
8
x
2
−
350
x
−
14
x
+
125
+
10
+
3
f
(
g
(
x
)
)
=
80
x
4
+
280
x
3
+
37
x
2
−
364
x
+
138
The answer is
f
(
g
(
x
)
)
=
80
x
4
+
280
x
3
+
37
x
2
−
364
x
+
138
.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Me no hablas Inglish sorry pal