Answer: a) 0.0792 b) 0.264
Step-by-step explanation:
Let Event D = Families own a dog .
Event C = families own a cat .
Given : Probability that families own a dog : P(D)=0.36
Probability that families own a dog also own a cat : P(C|D)=0.22
Probability that families own a cat : P(C)= 0.30
a) Formula to find conditional probability :
(1)
Similarly ,
Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792
b) Again, using (2)
Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264
Step-by-step explanation:
subtract-13 from -13 get zero
then, subtract 13 from 77 =64
then do divide 15 from 15
then divide 15 from 64 = 4.26 repeat
<span>You are given a car moved at a constant velocity during the first hour. It stopped for 2 hours at a mall and then moved ahead again at a constant velocity for the next 3 hours. Then you are given the car that has finally returned to its starting point with a constant velocity in the next 2.5 hours. The graph that best represents the car's motion is First straight line joins ordered pairs 0, 0 and 1, 60, second straight line joins 1, 60 and 3, 60, third straight line joins 3, 60 and 6, 100 and fourth straight line joins 6, 100 and 8.5, 0.</span>
The inequality of -1/12 >6 is 2
468 seats is the answer.
26 x 18
or
13 x 2 x 9 x 2
both equal 468
