Answer:
.095 laps per minute (if you need this answer as well 10.5 minutes per lap)
Step-by-step explanation:
(2/3)/7 =.095238 this is laps per min
7/(2/3)= 10.5 this is minutes per lap
I hope this is what you were looking for.
5x+2y = 20
For every hardcover book (x) you will be charged 5$.
For every paperback book (y) you will be charged 2$.
The amount of both types of books you buy has to be under or equal to 20$
Their GCF is 1. They don’t have any others that are the same
The way I like to figure out problems like this is to write it out like,
1/10 = x/6000
(One over ten equals x over 6000)
Then you find out how much you multiplied 10 by to get 6000. To do this you can divide 6000 by 10 getting 600. The rule "what you do to the bottom you have to do to top" in this equation. So since you multiplied the bottom by 600 you have to multiply the top by 600 as well. 600 times 1 is just 600.
So your answer is, 600 is 1/10 of 6000.
Hope this helps and isn't too confusing.
Answer:
(a)
- Independent Variable- Dosage of Omega-3 Fatty Acids
- Dependent Variable - Number of news item remembered
(b)Discrete
(c)Ratio Scale and Discrete Variable
(d) Experimental Method
Step-by-step explanation:
The psychologist wants to evaluate the claim that omega-3 fatty acids can help improve memory in normal adult humans.
(a)In the study, the participants in the two groups were given fish extracts containing Omega-3 (500 mg) and no Omega-3 (0 mg).
The memory test involves measuring the number of items each participant remembers from the past three weeks of news.
Therefore:
- Independent Variable- Dosage of Omega-3
- Dependent Variable - Number of news item remembered
(b) The dependent variable is discrete since the number of news items remembered can only be whole numbers.
(c)The independent variable is in milligrams of Omega-3 where the placebo is 0 mg. This is a ratio scale since it has an absolute zero.
Since the dosage is given in multiples of 50mg, it is a discrete variable.
(d)Since the psychologist seeks to manipulate the conditions of the study by introducing Omega-3 to some of the participants and placebo to other participants, it is an experimental distribution.