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prisoha [69]
3 years ago
10

There are white, blue, and red boats in a marina. Two-thirds of the boats in the marina are white, 4 7 of the remaining boats ar

e blue, and the rest are red. If there are 15 red boats, how many boats are in the marina?
Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
3 0

Answer: the number of boats that are in the marina is 105.

Step-by-step explanation:

Let x represent the number of boats that are in the marina.

Two-thirds of the boats in the marina are white. It means that the number of white boats in the marina is

2/3 × x = 2x/3

The remaining number of boats will be

x - 2x/3 = x/3

4/7 of the remaining boats are blue. It means that the number of boats that are blue is

4/7 × x/3 = 4x/21

The number of boats left would be

x/3 - 4x/21 = 3x/21

If there are 15 red boats, it means that

3x/21 = 15

3x = 21 × 15 = 315

x = 315/3

x = 105

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Let's call our unknown quantity n. We'll need to add n lbs of chocolate with a 1/15 ratio of cocoa butter to caramel to 300 lbs of chocolate with a 1/7 ratio of cocoa butter to caramel to yield 300+n lbs of chocolate with a 1/9 ratio of cocoa butter to caramel. We can set this up as an equation, but it's important to note something first: the ratio of the <em>caramel to the cocoa butter</em> is provided, but this is not the same thing as the <em>fraction of the chocolate the cocoa butter takes up</em>.

The 300 pounds of chocolate have 1 + 7 = 8 parts of cocoa butter and caramel total, which means that cocoa butter takes up 1/8 of those total parts; the n pounds we're adding on has 1 + 15 = 16 total parts, which means the cocoa butter takes up 1/16 of those; and the 300+n pounds being produced have 1 + 9 = 10 total parts, so the cocoa butter takes up 1/10 of those parts. With this in mind, we can set up the following equation:

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From here, it would be helpful to combine the fractions on the left side of the equation. To do this, we'll convert the denominator of \frac{300}{8} to 16, multiplying it by \frac{2}{2} to obtain the fraction \frac{600}{16}. Combining that with \frac{n}{16}, we have:

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To get rid of the denominator on the left, we'll multiply both sides of the equation by 16, and to eliminate the one on the right, we'll multiply both sides by 10:

(10)(16)\big( \frac{600+n}{16}\big)=\big( \frac{300+n}{10}\big)(10)(16)

Simplifying:

10(600+n)=(300+n)16\\ 6000+10n=4800+16n

And finally, we solve for n:

6000-4800=16n-10n\\ 1200=6n\\ 200=n

So, the confectioner needs 200 lbs of chocolate that's 1 part cocoa butter and 15 parts caramel.
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