3 years ago

Find the axis of symmetry of the graph of the function. f(x) = 2x^2 - 16x + 27

Mathematics

1 answer:

Marina CMI [18]3 years ago

4 0

Answer:

the axis of symmetry is x = 4

Step-by-step explanation:

The three coefficients of the polynomial f(x) = 2x^2 - 16x + 27 are a= 2, b = -16 and c = 27. -b

The formula for the axis of symmetry is x = ------------

-(-16)

which here is x = ------------ = 4

2(2)

The equation of the axis of symmetry is x = 4.

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Anna [14]

Answer:

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tangare [24]

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Step-by-step explanation:

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