All categories

3 years ago

the density of silver is 65.2g/cm3. if the volume of a piece of silver is 21.4cm3, what will the mass be in grams

Mathematics

1 answer:

lukranit [14]3 years ago

8 0

Answer:

mass - 1395.28 g

Step-by-step explanation:

density = mass / volume

65.2 g/cm^3 = mass / 21.4 cm^3

65.2 g * 21.4 = mass (cm^3 cancels out)

1395.28 g = mass

You might be interested in

Hi please i need the complete step-by-step solution for number 5. thank you

Nataliya [291]

Answer:

Step-by-step explanation:

( 12 + 3m ) / 2 = 18

12 + 3m = 18 x 2

12 + 3m = 36

3m = 36 - 12

3m = 24

m = 24 / 3

m = 8

5 0

2 years ago

Evaluate f(x)=e2x−1+2 when x=3. Give an approximate answer rounded to three decimal places.

olganol [36]

Answer:

f(3) ≈ 17.310

Step-by-step explanation:

e = 2.71828

Step 1: Define

f(x) = e2x - 1 + 2

x = 3

Step 2: Substitute and evaluate

f(3) = e2(3) - 1 + 2

f(3) = 6e + 1

f(3) = 16.3097 + 1

f(3) = 17.3097

f(3) ≈ 17.310

7 0

3 years ago

What is the volume of a right circular cone if the circumference of the base is 125.6 ft and the height is 75 ft.? Use π=3.14 an

Alex_Xolod [135]

Answer:

The volume of a right circular cone is $31400\ \text{feet}^3$ .

Step-by-step explanation:

The circumference of the base of a right circular cone is 125.6 ft.

Height of cone is 75 ft.

Circumference of base is :

$C=2\pi r$ , r is radius

$r=\dfrac{C}{2\pi}\\\\r=\dfrac{125.6}{2\times 3.14}\\\\r=20\ ft$

The volume of a cone is given by :

$V=\dfrac{1}{3}\pi r^2 h\\\\V=\dfrac{1}{3}\times 3.14\times (20)^2\times 75\\\\V=31400\ \text{feet}^3$

So, the volume of a right circular cone is $31400\ \text{feet}^3$ .

5 0

3 years ago

Evaluate log1∕6 36. please help

Sholpan [36]

$\log_{\tfrac 16} 36 \\\\\\=\dfrac{\ln 36}{ \ln \left(\tfrac 16\right)}\\\\\\=\dfrac{ \ln 6^2}{\ln (6^{-1})}\\\\\\=\dfrac{2 \ln 6}{-1 \ln 6}\\\\= - 2$

4 0

2 years ago

Whoever answers this correct gets most brainly!!

zzz [600]

D the last please tell me if I’m right thanks

5 0

3 years ago