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Kay [80]
3 years ago
12

the density of silver is 65.2g/cm3. if the volume of a piece of silver is 21.4cm3, what will the mass be in grams

Mathematics
1 answer:
lukranit [14]3 years ago
8 0

Answer:

mass - 1395.28 g

Step-by-step explanation:

density = mass / volume

65.2 g/cm^3 = mass / 21.4 cm^3

65.2 g * 21.4 = mass (cm^3 cancels out)

1395.28 g = mass

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Answer:

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Step-by-step explanation:

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2 years ago
Use these functions to answer the questions.
Elenna [48]
Part A
We have f\left(x\right)=\left(x+3\right)^2-1. To solve for the x-intercept, we set f(x) equal to 0.  That is
     \left(x+3\right)^2-1=0

     \left(x+3\right)^2=1

Take the square root of both sides, 
     x+3=1

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The x-intercept is (-2,0). 

To solve for the y-intercept, we set x=0. That is 
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The y-intercept is (0, 8) 

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Part B.
We have g\left(x\right)=-2x^2+8x+3.
Factor out -2
     =-2\left(x^2-4x\right)+3

Complete the square
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Part C
We have h\left(t\right)=-16t^2+28t.
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4 0
3 years ago
What is the equation of a line passing through (5,2) and parallel to the line represented by the equation y - 2x + 1?
34kurt

Step-by-step explanation:

Im not sure if its supposed y = -2x + 1 or y = 2x + 1 but I'll solve the problem for both.

First for y = -2x + 1

Since the line has to be parallel to y = -2x + 1

the slopes would be the same.

so, so far the equation would be

y = -2x + b

now we substitute (5,2) into the equation

2 = -2(5) + b

2 = -10 + b (Add 10 to both sides of the equation)

+10 +10

12 = b

Now that we solved for b

The equation would be

y = -2x + 12

^^ This equation is parallel to y = -2x + 1

Now to solve for an equation parallel to y = 2x + 1

Both equations would have the same slope

So far we would have

y = 2x + b

Now we solve for be by substituting the point (5,2)

2 = 2(5) + b

2 = 10 + b (subtract 10 from both sides)

-10 -10

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After solving for b

The equation is

y = 2x - 8

This equation is parallel to y = 2x + 1

4 0
2 years ago
Please help ill give brainiest
vaieri [72.5K]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
The quadrilateral ABCD is a rhombus with BD = BC. On the side
Andreas93 [3]
The halves of the rhombus separated by line BD are equilateral triangles.
  ∠BAD = 60°
so
  ∠ADM is 0.80*60° = 48°.

∠BMD is an exterior angle to ΔAMD, so is equal to the sum
  ∠BMD = ∠BAD + ∠ADM
  = 60° +48° = 108°

∠BMD = 108°
5 0
3 years ago
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