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sergiy2304 [10]
3 years ago
13

What is the largest number that can be produced by multiplying any three individual numbers from the following list [-2, 1, 3, -

8, 5, 9, -9, 4, 7, -7, 8]
Mathematics
2 answers:
nekit [7.7K]3 years ago
7 0
The answer is 648 multiply 9 and -9 and -8
neonofarm [45]3 years ago
4 0

we know that

To obtain the largest number that can be produced by multiplying any three individual numbers we have two cases

case 1) multiply the two largest negative numbers by the highest positive number

So

(-9)*(-8)*(9)=648

case 2) multiply the three largest positive numbers

(9)*(8)*(7)=504

648 > 504

therefore

the answer is

the numbers are -9,-8,9

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Step-by-step explanation:

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4 0
3 years ago
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posledela

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Read 2 more answers
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.3degreesF and a standard deviation of 0.73
faust18 [17]

Answer:

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher

Step-by-step explanation:

Data provided in the question:

sample size, n = 103

Mean temperature, μ = 98.3

°

Standard deviation, σ = 0.73

Degrees of freedom, df = n - 1 = 102

Now,

For Confidence level of 99%, and df = 102, the t-value = 2.62      [from the standard t table]

Therefore,

CI = (Mean - \frac{t\times\sigma}{\sqrt{n}},Mean + \frac{t\times\sigma}{\sqrt{n}})

Thus,

Lower limit of CI =  (Mean - \frac{t\times\sigma}{\sqrt{n}})

or

Lower limit of CI =  (98.3 - \frac{2.62\times0.73}{\sqrt{103}})

or

Lower limit of CI = 98.11

and,

Upper limit of CI =  (Mean + \frac{t\times\sigma}{\sqrt{n}})

or

Upper limit of CI =  (98.3 + \frac{2.62\times0.73}{\sqrt{103}})

or

Upper limit of CI = 98.49

Hence,

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher and  the mean temperature could very possibly be 98.6°F

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