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earnstyle [38]
3 years ago
6

If a polynomial function f(x) has roots 4 - 131 and 5, what must be a factor of f(x)?

Mathematics
1 answer:
pantera1 [17]3 years ago
5 0

Answer:

(x - 4), (x + 131), and (x - 5) must all be factors of f(x).

Step-by-step explanation:

You might be interested in
A student has 2 pounds of cereal. If the student eats 1/6 pound of cereal each day, how many days can the student eat cereal
harina [27]

Answer:

12 days

Step-by-step explanation:

1/6 per day

in 6 days- 1 pound

6x2=12 days=2 pounds

hope this helped :)

7 0
3 years ago
Read 2 more answers
I need help with both of those questions
mrs_skeptik [129]
Im nor sure which 2 you are reffering to, but I believe 5.1 x 10 to the power of 4 would be 51,000 and the shape with 3 unequal angles is a triangle?
4 0
3 years ago
Read 2 more answers
Will give brainliest if right
inn [45]

As the Remainder Theorem points out, if you divide a polynomial p(x) by a factor x – a of that polynomial, then you will get a zero remainder. Let's look again at that Division Algorithm expression of the polynomial:

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p(x) = (x – a)q(x) + r(x)

If x – a is indeed a factor of p(x), then the remainder after division by x – a will be zero. That is:

p(x) = (x – a)q(x)

In terms of the Remainder Theorem, this means that, if x – a is a factor of p(x), then the remainder, when we do synthetic division by

x = a, will be zero.

The point of the Factor Theorem is the reverse of the Remainder Theorem: If you synthetic-divide a polynomial by x = a and get a zero remainder, then, not only is x = a a zero of the polynomial (courtesy of the Remainder Theorem), but x – a is also a factor of the polynomial (courtesy of the Factor Theorem).

Just as with the Remainder Theorem, the point here is not to do the long division of a given polynomial by a given factor. This Theorem isn't repeating what you already know, but is instead trying to make your life simpler. When faced with a Factor Theorem exercise, you will apply synthetic division and then check for a zero remainder.

Use the Factor Theorem to determine whether x – 1 is a factor of

    f (x) = 2x4 + 3x2 – 5x + 7.

For x – 1 to be a factor of  f (x) = 2x4 + 3x2 – 5x + 7, the Factor Theorem says that x = 1 must be a zero of  f (x). To test whether x – 1 is a factor, I will first set x – 1 equal to zero and solve to find the proposed zero, x = 1. Then I will use synthetic division to divide f (x) by x = 1. Since there is no cubed term, I will be careful to remember to insert a "0" into the first line of the synthetic division to represent the omitted power of x in 2x4 + 3x2 – 5x + 7:

completed division: 2  2  5  0  7

Since the remainder is not zero, then the Factor Theorem says that:

x – 1 is not a factor of f (x).

Using the Factor Theorem, verify that x + 4 is a factor of

     f (x) = 5x4 + 16x3 – 15x2 + 8x + 16.

If x + 4 is a factor, then (setting this factor equal to zero and solving) x = –4 is a root. To do the required verification, I need to check that, when I use synthetic division on  f (x), with x = –4, I get a zero remainder:

completed division: 5  –4  1  4  0

The remainder is zero, so the Factor Theorem says that:

x + 4 is a factor of 5x4 + 16x3 – 15x2 + 8x + 16.

In practice, the Factor Theorem is used when factoring polynomials "completely". Rather than trying various factors by using long division, you will use synthetic division and the Factor Theorem. Any time you divide by a number (being a potential root of the polynomial) and get a zero remainder in the synthetic division, this means that the number is indeed a root, and thus "x minus the number" is a factor. Then you will continue the division with the resulting smaller polynomial, continuing until you arrive at a linear factor (so you've found all the factors) or a quadratic (to which you can apply the Quadratic Formula).

Using the fact that –2 and 1/3 are zeroes of  f (x) = 3x4 + 5x3 + x2 + 5x – 2, factor the polynomial completely.   Copyright © Elizabeth Stapel 2002-2011 All Rights Reserved

If x = –2 is a zero, then x + 2 = 0, so x + 2 is a factor. Similarly, if x = 1/3 is a zero, then x – 1/3 = 0, so x – 1/3 is a factor. By giving me two of the zeroes, they have also given me two factors: x + 2 and x – 1/3.

Since I started with a fourth-degree polynomial, then I'll be left with a quadratic once I divide out these two given factors. I can solve that quadratic by using the Quadratic Formula or some other method.

The Factor Theorem says that I don't have to do the long division with the known factors of x + 2 and x – 1/3. Instead, I can use synthetic division with the associated zeroes –2 and 1/3. Here is what I get when I do the first division with x = –2:

completed divison: bottom row:  3  –1  3  –1  0

The remainder is zero, which is expected because they'd told me at the start that –2 was a known zero of the polynomial. Rather than starting over again with the original polynomial, I'll now work on the remaining polynomial factor of 3x3 – x2 + 3x – 1 (from the bottom line of the synthetic division). I will divide this by the other given zero, x = 1/3:

completed division:  bottom row:  3  0  3  0

 

3x2 + 3 = 0

3(x2 + 1) = 0

x2 + 1 = 0

x2 = –1

x = ± i

If the zeroes are x = –i and x = i, then the factors are x – (–i) and x – (i), or x + i and x – i. I need to   divided off a "3" when I solved the quadratic; it is still part of the polynomial, and needs to be included as a factor. Then the fully-factored form is:

3x4 + 5x3 + x2 + 5x – 2 = 3(x + 2)(x – 1/3)(x + i)(x – i)

7 0
3 years ago
Can somone help? ill give brainlist
ale4655 [162]

Answer:

13.99+.75+.75=15.49

Part A ) 15.49

Part B) Anna is correct because her pizza only cost 15.49 and if you subtract 15.49 from 20 it is 14.51

Step-by-step explanation:

6 0
2 years ago
Select all the distribution shapes for which it is most often appropriate to use the mean .
goblinko [34]

The distribution shape that tells us for which it is best to use the mean is the skewed.

<h3>What is the mean?</h3>

This is the term that is used to refer to the average score that exists in a data set.

In the question, these are the reasons why the other options are not correct

When we say Bimodal we are talking about the 2 modes that are in a symmetric distribution. This has nothing to do with the mean

The bell shape has to do with how the normal distribution is when it is drawn. It would create a bell shape hence the mean is not useful.

symmetric has to do with the fact that there are mirror images when the vertical line is drawn in the distribution.

Uniformed shapes tells us that the classes are made up of the same frequency all through.

The skewed shape is what tells us if the median is more or if it is less.

Hence we have the answer that the distribution shapes for which it is most often appropriate to use the mean is the skewed.

Read more on the mean here

brainly.com/question/17847237

#SPJ1

4 0
1 year ago
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