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earnstyle [38]
4 years ago
6

If a polynomial function f(x) has roots 4 - 131 and 5, what must be a factor of f(x)?

Mathematics
1 answer:
pantera1 [17]4 years ago
5 0

Answer:

(x - 4), (x + 131), and (x - 5) must all be factors of f(x).

Step-by-step explanation:

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Need help with question
son4ous [18]

Answer:

2nd option is correct

Step-by-step explanation:

this would be using the ASA congruence theorem.

6 0
2 years ago
What is 1/3 x²+2 x=3​
allsm [11]
5. if x=3 then replace x with 3. 3^2 is 9, 1/3 of 9 is 3, 3+2 = 5
3 0
3 years ago
Classify each of the following rational or irrational
romanna [79]

In mathematics, a rational number is any number that can be expressed as a ratio​ of two integers numbers, being a non-zero denominator.

Answers​

-5 is rational because can be writen as -5/1​

√11 is irrational because can't be written as a ratio.​

2/3 is rational because is a ratio of two integer numbers.​

0.5 is rational because can be written 1/2​

√16 is rational because can be written 4/1​

pi (π) is irrational because can't be written as a ratio

\textit{\textbf{Spymore}}​​

7 0
3 years ago
Justify each step of the proof.
WARRIOR [948]
 <span>I assume that the x is squared 
(on Yahoo!Answers, we often use the caret ^ to show a power or an exponent) 
(think of it as a tiny arrow pointing up, showing that the following number should be seen as if it were raised above the line) 

2(x^2 + 5) = 60 

Can it be x = 5 ? 
we test: 
2(5^2 + 5) = 2(25 + 5) = 2(30) = 60 
it works, therefore x = 5 is a solution. 

Can it be x = -5? 
we test again: 
2[(-5)^2 + 5) = 2(25 + 5) = 2(30) = 60 
it works, therefore x = -5 is also a solution. 

The way you did it, there could be some confusion between step 4 and step 5 (because you do not explain how you go from 4 to 5). 
If you simply "take the square root" on both sides, someone could argue that the "principal" square root of a number is the positive value (+5 only, not -5). On the other hand, if you state: 
(after step 4), we look for all values that give 25 when they are squared, then -5 is allowed. 

The way the conjecture is stated at the beginning, the easiest way is to check both values to find out that, yes, they are both valid solutions.</span>
7 0
3 years ago
Evaluate the expression a + c for a = 22 and c = 11.
bixtya [17]

Answer: 33

Step-by-step explanation: substitute a with 22 and c with 11.

22+11=33

4 0
3 years ago
Read 2 more answers
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