Help solving this math homework

Which choice provides the best evidence for the

vodka [1.7K]

Correct option is B, Lines 39-42 ("Normally . . . community")

The "matter of urgency," as Akira explains in lines 39–42, is that he has "an opportunity to go to America, as dentist for Seattle's Japanese community." Chie's response to Akira's marriage proposal is necessary for him to determine whether or not to take the position in Seattle.

The answers to the previous question are not well supported by the evidence in Choices A, C, and D. Choice A is wrong since Akira apologizes for disturbing Chie's peaceful evening in line 39. Lines 58–59 discuss the gravity of Akira's demand, not its immediacy, hence option C is incorrect.

Line 73 merely demonstrates that Akira's suggestion "startled" Chie, not why his request is time-sensitive, hence option D is incorrect.

Here's another question with an answer similar to this Chie and Akira:

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2 years ago

How many times greater is 46 than 0.46?NO DEVIDING

Inessa [10]

100 because if you move the decimal over two places that is equivalent to multiplying 0.46 by 100

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3 years ago

Russell deposited $200 to open a new bank account before he paid $250 for his portion of the rent. His bank charged him a $50 ov

icang [17]

300 dollars I think is it multiple choice

4 0

3 years ago

Chau's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Chau

Elena-2011 [213]

He used 74.4 lbs of type A coffee.
If he is using a mixture of two divide the total of cost by 2 to get the amount of what one of the coffee costed, then divide that by 5.55 and you get the answer.

6 0

3 years ago

the first four terms in an arithmetic sequence are $x y$, $x - y$, $xy$, and $x/y$, in that order. what is the fifth term?

olga2289 [7]

When the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be $\frac{123}{40}$

A sequence of numbers in which every term (except the first term) is obtained by adding a constant number to the previous term is called an arithmetic sequence

In given arithmetic sequence

The first term = x+y

The second term = x-y

Then, the common difference= (x-y)-(x+y)

x-y-x-y= -2y

The third term = x-y+(-2y)

x-y-2y= x-3y

In question third term is given as xy

So both are equal

x-3y=xy

-3y=xy-x

-3y=x(y-1)

x= $\frac{-3y}{y-1}$

Similarly fourth term will be

x-3y-2y=x-5y

$x-5y=\frac{x}{y}$

substitute the value of x in the equation

$\frac{-3y}{y-1}-5y=\frac{\frac{-3y}{y-1} }{y} \\\frac{-3y}{y-1} -5y=\frac{-3}{y-1}\\ -3y-5y(y-1)=-3\\-3y-5y^{2}+5y=-3\\ -5y^{2} +2y+3=0\\5y^{2} -2y-3=0$