1 1/12
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(1/3, 3/4) = 12
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
(13×44)+(34×33)=?
Complete the multiplication and the equation becomes
4/12+9/12=?
The two fractions now have like denominators so you can add the numerators.
Then:
4+9/12=13/12
This fraction cannot be reduced.
The fraction
13/12
is the same as
13÷12
Convert to a mixed number using
long division for 13 ÷ 12 = 1R1, so
1312=1 1/12
Therefore:
13+34=1 11/2
Step-by-step explanation:
I think the typing of the answer options must have some typos.
the magnitude of a vector is the length of the vector.
the length of the vector is Pythagoras over its coordinates.
this vector goes from (3, -6) to (-4, 1), so the relative vector coordinates are -4 - 3 and 1 - -6 = -7, 7.
so the magnitude of length of the vector is
sqrt((-7)² + 7²) = sqrt(49+49) = sqrt(98)
= 9.899494937...
the direction angle is the angle of the vector with the x-axis.
it is the inverse tan of y/x. and in this case in the second (upper left) quadrant, since the vector is pointing up and left.
the inverse tan of 7/-7 = inverse tab of 1/-1 =
inverse tan of -1 in the second quadrant is 135°.
we know that the multiplication comes first in the family then we start from left to right
4 x 5= 20
9-20 = -11
-11 + 6 = -5
there you go!
Answer:
give y is equal to 2
substituting the value of y, we get
4x -y = 10
4x=10 +2
4x=12
x=12÷4
therefore x =3
Answer:
The binomial: (x-2) (second option of the list) is a factor of the given trinomial
Step-by-step explanation:
You are looking for two binomial factors of the form; (x+a) and (x+b), with values "a" and "b" such that:
Their product "a times b" results in: "+14" (the numerical term in the initial trinomial 
,
and their combining "a+b" results in "-9" (the coefficient in the middle term of the trinomial)
Such number "a" and "b" are: "-2" and "-7".
We can see by multiplying the binomials formed with these numbers:
(x-2) and (x-7) that their product indeed renders the original trinomial:
therefore, the binomials (x-2) and (x-7) are factors of the given trinomial.
The only one shown among the four possible options is then: (x-2)
