All categories

3 years ago

find the equation for the line perpendicular to y=4/3x+1 with y-intercept 0,15 in slope-intercept form

Mathematics

1 answer:

drek231 [11]3 years ago

7 0

Answer:

y = (-3/4)x + 15

Step-by-step explanation:

The slope of the given line is 4/3. The slope of a line perpendicular to this given line is the negative reciprocal of 4/3, which comes out to -3/4.

Now that we have both the slope and y-intercept of the new line, we're ready to write out the desired equation in slope-intercept form:

y = (-3/4)x + 15

You might be interested in

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

Graph f(x)=2x+1 and g(x)=−x+7 on the same coordinate plane.

Tamiku [17]

Answer:

x = 2

Step-by-step explanation:

To solve the equation, you need to set both functions equal to each other and simplify to find the value of "x".

f(x) = 2x + 1

g(x) = -x + 7

f(x) = g(x) <----- Given equation

2x + 1 = -x + 7 <----- Insert functions

3x + 1 = 7 <----- Add "x" to both sides

3x = 6 <----- Subtract 1 from both sides

x = 2 <----- Divide both sides by 3

8 0

1 year ago

What is the surface area of the right cylinder below. radius 3 height 7

lina2011 [118]

Answer:

160 sq. uits

Step-by-step explanation:

160 sq. uits é a resposta

4 0

2 years ago

Multiply: (-4 + i)(-1 + 5i)

Olegator [25]

Answer:

$( - 4 + i) ( - 1 + 5i) \\ = 4 - 20i - 1i + 5 {i}^{2} \\ = 4 - ( -21i )+ 5i {}^{2}$

3 0

3 years ago

How many odd numbers are there between twenty and forty?

inna [77]

Answer:

Total 10

Step-by-step explanation:

21. 23, 25, 27, 29, 31 , 33, 35, 37, 39.

hope this helps you

5 0

2 years ago