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Anna007 [38]
3 years ago
13

On a frictionless track,cart 1 is moving with a constant,rightward(+) velocity of 1.0m/s.Cart 2 is also moving rightward with co

nstant velocity of 5.0m/s. After a while,cart 2 collides cart 1 from behind.(It is an elactic collision.)If the final velocity of cart 2 becomes 3.0m/s, what is the final velocity of cart 1?
Physics
1 answer:
mamaluj [8]3 years ago
4 0

Answer:

The final velocity of cart 1 is 3m/s

Explanation:

From principle of conservation of linear momentum, which states that sum of the momentum before collision is equal to the sum of the momentum after collision.

Momentum, P is given as mass x velocity.

ΔP = Δmv = m₁u₁ +m₂u₂ = m₁v₁ + m₂v₂

Assumptions:

  • If the two carts are moving on frictionless track, then limiting frictional forces due to their weights are negligible.
  • After the elastic collision, the two carts will move separately with different velocity

u₁ + u₂ = v₁ + v₂;

where;

u₁ and u₂  are the initial velocity for cart 1 and cart 2 respectively

v₁ and v₂  are the final velocity for cart 1 and cart 2 respectively

1 m/s + 5 m/s = v₁  + 3m/s

6 m/s =  v₁  + 3m/s

v₁  = 6 m/s - 3m/s = 3m/s

Therefore, the final velocity of cart 1 is 3m/s

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Answer:

\omega=943\ rad/s

Explanation:

Given that,

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The kinetic energy of the disk is given by :

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3 years ago
A car starts from rest and moves along the positive x-axis with a constant acceleration of 5 m/s/s for 8 seconds. It then contin
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Answer:

340

Explanation:

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option A.

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The correct answer is option A.

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By method of dimension show that the following equation are homogenous.
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Answer:

Proof in explanataion

Explanation:

The basic dimensions are as follows:

MASS = M

LENGTH = L

TIME = T

i)

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H = \frac{u^2Sin^2\phi}{2g}

where,

H = height (meters)

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g = acceleration due to gravity (m/s²)

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H = [L]

u = [LT⁻¹]

g = [LT⁻²]

Sin Ф = no dimension

Therefore,

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<u>[L] = [L]</u>

Hence, the equation is proven to be homogenous.

ii)

F = \frac{Gm_1m_2}{r^2}\\\\

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