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Wewaii [24]
3 years ago
10

How do I solve the following problem?

Physics
1 answer:
lukranit [14]3 years ago
7 0
Use the impulse-momentum theorem.

Ft = mv

Substitute your known values:

(120kg)(20m/s) = F(1.5)

F= 1600N

Hope this helps!
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A laser is placed at the point $(3,5)$. The laser beam travels in a straight line. Larry wants the beam to hit and bounce off th
Black_prince [1.1K]

Answer:

4units

Explanation:

To calculate the total distance the beam will travel along this path, you will use the formula for calculating the distance between two coordinates expressed as;

D = √(x2-x1)²+(y2-y1)²

Given the coordinate points

(3,5) and (7,5)

Substitute

D = √(7-3)²+(5-5)²

D = √(7-3)²+0²

D = √4²

D = √16

D = 4

Hence the total distance the beam will travel along this path is 4units

6 0
3 years ago
A proton at location A makes an electricfield E-->1 atlocation B. A different proton, placed atlocation B, experiences a forc
luda_lava [24]

Answer:

Explanation:

 |F-->1| =  E-->1 x charge on proton

= 300 x 1.6 x 10⁻¹⁹

Magnitude of electric force on proton

|F-->1| = 480 x 10⁻¹⁹ N .

Inside lithium nucleus , there are three protons so charge on it

= 3 x 1.6 x 10⁻¹⁹ = 4.8 x 10⁻¹⁹ C .

Magnitude of electric force on lithium nucleus

|F-->Li|  =   E-->1 x charge on lithium nucleus

= 300 x  4.8 x 10⁻¹⁹

= 1440 x 10⁻¹⁹ N .

Electron has same charge as that possessed by proton so charge on electron = 1.6 x 10⁻¹⁹ C

Magnitude of force on electron

|F-->1| =  E-->1 x charge on electron

= 300 x 1.6 x 10⁻¹⁹

=  480 x 10⁻¹⁹ N .

7 0
3 years ago
How can you say metre cube is a derived unit​
riadik2000 [5.3K]

Answer:

The newton (lowercase n!) is a derived unit because its definition consists of multiplication of three defined base units and nothing else. Its meaning is thus derived, not independently defined.

8 0
2 years ago
Question 5 (1 point)
Tom [10]

Answer: 18000 coulombs

Explanation:

Given that:

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Time, T = 1 hour

(The SI unit of time is seconds. So, covert 1.0 hour to seconds)

If 1 hour = 60 minutes and 60 seconds = 1 minute

Then, 1.0 hour = (60 x 60)

= 3600 seconds

Since electric charge, Q = current x time

i.e Q = I x T

Q = 5.0 A x 3600 seconds

Q = 18000 coulombs

Thus, 18000 coulombs of charge flows through the lamp in this time.

4 0
3 years ago
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