A rectangular metal bar has length of 20cm, width of 5cm. Mass of the block is 2kg and its density is 5000kg/m3. Find the height
1 answer:
You might be interested in
Answer:
The magnitude of the electric field is
Explanation:
Given that,
Time t = 2.10 s
Speed = 160 m/s
Specific charge =Ratio of charge to mass = 0.100 C/kg
We need to calculate the acceleration
Using equation of motion
Put the value into the formula
We need to calculate the magnitude of the electric field
Using formula of electric field
Put the value into the formula
The direction is upward.
Hence, The magnitude of the electric field is
Complete question:
Point charges q1=- 4.10nC and q2=+ 4.10nC are separated by a distance of 3.60mm , forming an electric dipole. The charges are in a uniform electric field whose direction makes an angle 36.8 ∘ with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 7.30×10−9 N⋅m ? Express your answer in newtons per coulomb to three significant figures.
Answer:
The magnitude of this field is 826 N/C
Explanation:
Given;
The torque exerted on the dipole, T = 7.3 x 10⁻⁹ N.m
PEsinθ = T
where;
E is the magnitude of the electric field
P is the dipole moment
First, we determine the magnitude dipole moment;
Magnitude of dipole moment = q*r
P = 4.1 x 10⁻⁹ x 3.6 x 10⁻³ = 1.476 x 10⁻¹¹ C.m
Finally, we determine the magnitude of this field;
E = 826 N/C (in three significant figures)
Therefore, the magnitude of this field is 826 N/C