Answer: 0.04m
Explanation:
Mass of the block (m) = 2kg
density (p) = 5000kg/m3
Volume (v) = ?
Recall that density is obtained by dividing mass by volume. i.e density = mass / volume
p = m / v
Make v the subject formula
v = m / p
So, v = 2kg / 5000kg/m3
v = 0.0004 m3
Now given that the volume of the rectangular metal bar is 0.0004m3, find its height:
length of metal bar (l) = 20cm
convert length in centimeters to meters
(If 100cm = 1m
20cm = 20/100 = 0.2m)
width of bar (w) = 5cm
convert width in centimeters to meters
(If 100cm = 1m
5cm = 5/100 = 0.05m)
height (h) = ?
Volume of metal bar = l x w x h
0.0004 m3 = 0.2m x 0.05m x h
0.0004 m3 = 0.2m x 0.05m x h
0.0004 m3 = 0.01m² x h
h = 0.0004 m3 / 0.01m²
h = 0.04m
Thus, the height of the rectangular metal bar is 0.04 meters
