Answer:
answer is 0.1428
Explanation:
Data:- vf=5.0 , vi=0.0 , t=35 , a=? so appling first eq of motion vf=vi+at we have to find a=vf-vi/t , a=5.0-0.0/35 , a=5/35 ,a=0.1428m/sec²
<span>Work, very simply, equals force times distance (when the force and distance are in the same direction. otherwise you get a little bit of trig added on) \[W=F*\Delta x\] W=70N * 9.0 m = 630 Nm = 630 J</span>
Answer
Given,
Energy absorbed, 
Energy expels,
Temperature of cold reservoir, T = 27°C
a) Efficiency of engine
b) Work done by the engine
c) Power output
t = 0.296 s
