A circle with the equation (x + 4)2 + (y + 2)2 = 36 is reflected over the line x = 1. What is the equation of the image? (x + 4)

Question

uranmaximum [27]

4 years ago

10

A circle with the equation (x + 4)2 + (y + 2)2 = 36 is reflected over the line x = 1. What is the equation of the image? (x + 4)

2 + (y - 2)2 = 36 (x - 6)2 + (y + 2)2 = 36 (x + 6)2 + (y - 2)2 = 36 (x - 4)2 + (y + 2)2 = 36

Mathematics

2 answers:

Nataly_w [17] · Answer 1 · 2022-01-19T09:43:37+03:00

Nataly_w [17]4 years ago

8 0

Answer:

(x - 6)² + (y + 2)² = 36

Step-by-step explanation:

Centre before reflection: (-4,-2)

Centre after reflection:

(-4+5+5,-2) = (6,-2)

(x - 6)² + (y + 2)² = 36

Rasek [7] · Answer 2 · 2022-01-19T08:19:39+03:00

Answer:

B

Step-by-step explanation:

Currently, the graph looks like the attachment.

The centre of this circle is at (-4, -2), but when we flip it over the line x = 1 (the blue line on the picture), the centre will become ((1- -4) + 1, -2) = (6, -2).

Look for the equation $(x-h)^2+(y-k)^2=r^2$ that matches this center. We want the center (h, k) to be (6, -2), so our equation should look something like:

$(x-6)^2+(y+2)^2=36$

The answer is B.