<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection )
p(getting 2 good coils for second selection)
p(first selection) = p(second selection) = 
Hence, p(getting 2 good coil for two selection) = 
simply multiply the cost of the large pool equipment set by three to get the answer. So, $1,042*3= $3126
Answer:
50, 58, 66
Step-by-step explanation:
it looks like a (+8) pattern
found this online, hope it helps !!