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3 years ago

I need help finding the degree of rotation for number 5 and 6

Mathematics

1 answer:

stiks02 [169]3 years ago

7 0

Answer:

Step-by-step explanation:

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The movement of the progress bar may be uneven because questions can be worth more or less (including zera

kakasveta [241]

Answer:

600

Step-by-step explanation:

Because the tens digit is less than 5, round down to 600

5 0

2 years ago

Read 2 more answers

124 ounces decreased by 67%

slavikrds [6]

40.92 ounces.
You can find it by multiplying 124 by 0.33

8 0

3 years ago

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Rewrite in standard form identify the degree of the polynomial and the number of terms

Alenkasestr [34]

Standard Form: ax² + bx + c = y

Basically, you put all the numbers from greatest to least with exponents then variables.

We have the numbers:

-x²

2x^5

-7x

Put these numbers from least to greatest from the exponents.

2x^5 - x² - 7x + 9

The degree of the polynomial is the number with the greatest exponent. In this case, the highest exponent is 5.

The degree of the polynomial is 5.

Best of Luck!

7 0

3 years ago

What is the equation in point-slope form of the line passing through (4, 0) and (2, 6)? (5 points) y = 4x − 2 y = 2x − 4 y = −3(

DIA [1.3K]

For this case we have that by definition, the point-slope equation of a line is given by:

$y-y_ {0} = m (x-x_ {0})$

We have the following points:

$(x_ {1}, y_ {1}) :( 2,6)\\(x_ {2}, y_ {2}) :( 4,0)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0-6} {4-2} = \frac {-6} {2} = -3$

We chose a point:

$(x_ {0}, y_ {0}) :( 4,0)$

Substituting in the equation we have:

$y-0 = -3 (x-4)\\y = -3 (x-4)$

Finally, the equation is: $y = -3 (x-4)$

Answer:

OPTION C

6 0

3 years ago

Read 2 more answers

US average math SAT scores follow a normal distribution with a mean of 505 and a standard deviation of 112. A sample of 64 enter

Hitman42 [59]

Answer:

The claim that the scores of UT students are less than the US average is wrong

Step-by-step explanation:

Given : Sample size = 64

Standard deviation = 112

Mean = 505

Average score = 477

To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.

Solution:

Sample size = 64

n > 30

So we will use z test

$H_0:\mu \geq 477\\H_a:\mu < 477$

Formula : $z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

$z=\frac{505-477}{\frac{112}{\sqrt{64}}}$

$z=2$

Refer the z table for p value

p value = 0.9772

α=0.05

p value > α

So, we accept the null hypothesis

Hence The claim that the scores of UT students are less than the US average is wrong

3 0

3 years ago