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sasho [114]
3 years ago
8

Collins has a part-time job as a dog walker. The table below shows the amount of money Collins earned for different numbers of h

ours of work: Collins' Earnings from Dog Walking Number of Hours Worked Money Earned (dollars) 5 30 6 36 8 66 Part A: What are the missing numbers in the table? Show your work. (4 points) Part B: Collins also does part-time yard work. The ratio of the number of hours Collins works to the money he earns in dollars is 1:7. Create a table to show the money earned by Collins for 5, 6, and 8 hours of doing yard work. (3 points) Part C: How many more dollars does Collins earn doing yard work for 5 hours than working as a dog walker for 5 hours? Show your work. (3 points) Question 3 (Essay Worth 10 points) (02.05 MC) Mike surveyed 250 teenagers to find out their favorite food. He found that 76% of the teenagers surveyed like burgers. Part A: How many teenagers surveyed like burgers? Show your work. (4 points) Part B: In another survey, Jane found that 25% of the total number of teenagers surveyed like sandwiches. If 50 teenagers like sandwiches, what is the total number of teenagers that Jane surveyed? Show your work. (4 points) Part C: Give an example of a situation in which a percentage is greater than 100%. (2 points) Question 4 (Essay Worth 10 points) (02.06; 02.07 MC) Part A: James bought a cake that weighs 3 and 1 over 4 pounds. How many ounces does the cake weigh? Show your work. (5 points) [16 ounces = 1 pound] Part B: A running tap dispenses 0.15 gallons of water every second. How many pints of water is dispensed after 20 seconds? Show your work. (5 points) [1 gallon = 4 quarts, 1 quart = 2 pints] You must check the box below prior to submitting your exam! Check this box to indicate you are ready to submit your exam Explorer Toolbox Workload My Folders Current course: 4026 FDK201.10
Mathematics
1 answer:
Galina-37 [17]3 years ago
5 0

Answer:

Part C:  Collins makes $5 more when working 5 hours as a yard worker than when he was walking dogs.

Step-by-step explanation:

i made charts, for dog walking and yard work, then compared them.

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Tan(x+pi/2)= negative cot x
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I'm only going to alter the left hand side. The right side will stay the same the entire time

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I'll also use sin(x+y) = sin(x)cos(y)+cos(x)sin(y) and cos(x+y) = cos(x)cos(y)-sin(x)sin(y)

So with that in mind, this is how the steps would look:

tan(x+pi/2) = -cot x
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(sin(x)cos(pi/2)+cos(x)sin(pi/2))/(cos(x)cos(pi/2)-sin(x)sin(pi/2)) = -cot x
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Identity is confirmed

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Unless you show a picture, its impossible to solve.
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Answer:

π − 12

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lim(u→0) (sin(πu + 2π) + 8 − u³ − 6u² − 12u − 8) / u

lim(u→0) (sin(πu + 2π) − u³ − 6u² − 12u) / u

Using angle sum formula:

lim(u→0) (sin(πu) cos(2π) + sin(2π) cos(πu) − u³ − 6u² − 12u) / u

lim(u→0) (sin(πu) − u³ − 6u² − 12u) / u

Divide:

lim(u→0) [ (sin(πu) / u) − u² − 6u − 12 ]

lim(u→0) (sin(πu) / u) + lim(u→0) (-u² − 6u − 12)

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Multiply and divide by π.

lim(u→0) (π sin(πu) / (πu)) − 12

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Use special identity, lim(x→0) ((sin x) / x ) = 1.

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