To solve this problem you must apply the following proccedure:
1. <span>You have a total of 21 coins, all nickels and dimes. Then:
x:nickels=5 cents
y: dimes=10 cents
x+y=21
2. You have that the total value is $1.70. Then:
5x+10y=170
3. The system of equation is:
x+y=21 (i)
5x+10y=170 (ii)
4. You have:
x+y=21
x=21-y
5(21-y)+10y=170
105-5y+10y=170
y=13 dimes
x+13=21
x=8 nickels</span>
Ok, base area: triangle sides are 25cm each, or .25m
s=semiperimeter
area=s(sqrt(s-side)^3)
s=75/2
s-side=37.5-25=12.5
area=37.5*12.5*sqrt12.5
let E6 mean 10^6
.075E6m=1/3 (37.5*12.5*(sqrt12.5))h
solve for h
I get:137cm
I hope that helped
- The value of the n is 8.
- There are 7 positive integers between 100 and 200 which are divisible by 14.
<u>Step-by-step explanation:</u>
The sum of first n odd positive integer is n^2. The nth odd number is 2n-1.
i.e. 1 + 3 + ........+ (2n-1) = n^2.
1 + 3 +..........+ (2n-1) = 64
n^2 = 64
n = 8.
The positive integers between 100 and 200 which are divisible by 14 are 112, 126, 140, 154, 168, 182, 196. It is obtained by the multiples of 14 between 100 and 200.
100 = 7 * 14 + 2
200 = 14 * 14 + 4. The answer is 14 - 7 = 7
The seven numbers are
14 * 8 = 112
14 * 9 = 126
14 * 10 = 140
14 * 11 = 154
14 * 12 = 168
14 * 13 = 182
14 * 14 = 196
ANSWER SHOWN IN THE DOCUMENT ATTACHED TO THIS