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3 years ago

Pick 2 and show work

Mathematics

1 answer:

olga2289 [7]3 years ago

6 0

3x+2y-4z=12 add 4z on both sides
3x+2y=12+4z subtract 2y on both sides
3x=12+4z-2y divide 3 on both sides
x= 4+4/3z-2/3y
x= 4+1.25z-.67y

3x+2y-4z=12 subtract 3x on both sides
2y-4z=12-3x add 4z to both sides
2y=12-3x+4z divide 2 on both sides
y=6-3/2x+4/2z
y=6- 1.5x+2z

3x+2y-4z=12 subtract 3x on both sides
2y-4z=12-3x subtract 2y on both sides
-4z=12-3x-2y divide by -4 on both sides
z=-3-3/4x-2/4y
z=-3-.75x-.5y

your welcome you can do the other one

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Answer: Choice B) 1/3, 1/4, 1/5, 1/6

=============================================

Plug in n = 1 to find the first term

a_n = ( (n+1)! )/( (n+2)! )

a_1 = ( (1+1)! )/( (1+2)! )

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a_1 = ( 2*1 )/( 3*2*1 )

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a_1 = 1/3

The first term is 1/3. Optionally you can stop here because only choice B has 1/3 listed as the first term, so this must be the answer. However, I'm going to keep going to show how to find the three other terms. This will help confirm why choice B is the answer, and it will be handy for those times when you aren't given multiple choice answers.

------------

Plug in n = 2

a_n = ( (n+1)! )/( (n+2)! )

a_2 = ( (2+1)! )/( (2+2)! )

a_2 = ( 3! )/( 4! )

a_2 = ( 3*2*1 )/( 4*3*2*1 )

a_2 = 6/24

a_2 = 1/4

The second term is 1/4

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Plug in n = 3

a_n = ( (n+1)! )/( (n+2)! )

a_3 = ( (3+1)! )/( (3+2)! )

a_3 = ( 4! )/( 5! )

a_3 = ( 4*3*2*1 )/( 5*4*3*2*1 )

a_3 = 24/120

a_3 = 1/5

The third term is 1/5

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Plug in n = 4

a_n = ( (n+1)! )/( (n+2)! )

a_4 = ( (4+1)! )/( (4+2)! )

a_4 = ( 5! )/( 6! )

a_4 = ( 5*4*3*2*1 )/( 6*5*4*3*2*1 )

a_4 = 120/720

a_4 = 1/6

The fourth term is 1/6

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The first four terms are: 1/3, 1/4, 1/5, 1/6, so that confirms why choice B is the answer.

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Normally distributed data is the distribution of probability which is symmetric about the mean.

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