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3 years ago

Pick 2 and show work

Mathematics

1 answer:

olga2289 [7]3 years ago

6 0

3x+2y-4z=12 add 4z on both sides
3x+2y=12+4z subtract 2y on both sides
3x=12+4z-2y divide 3 on both sides
x= 4+4/3z-2/3y
x= 4+1.25z-.67y

3x+2y-4z=12 subtract 3x on both sides
2y-4z=12-3x add 4z to both sides
2y=12-3x+4z divide 2 on both sides
y=6-3/2x+4/2z
y=6- 1.5x+2z

3x+2y-4z=12 subtract 3x on both sides
2y-4z=12-3x subtract 2y on both sides
-4z=12-3x-2y divide by -4 on both sides
z=-3-3/4x-2/4y
z=-3-.75x-.5y

your welcome you can do the other one

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3 years ago

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3 years ago

Determine whether this pair of lines is parellel, perpendicular, or neither 6+2x=3y 3x+2y=9 Choose the correct answer below. A.

andriy [413]

Answer:

Option A. These two lines are perpendicular

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are equal

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

step 1

Convert the given equation A in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$6+2x=3y$ ----> equation A

Solve for y

That means----> isolate the variable y

Divide by 3 both sides

$y=\frac{2}{3}x+2$

$m_A=\frac{2}{3}$

step 2

Convert the given equation B in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$3x+2y=9$ ----> equation B

Solve for y

That means----> isolate the variable y

subtract 3x both sides

$2y=-3x+9$

Divide by 2 both sides

$y=-\frac{3}{2}x+4.6$

$m_B=-\frac{3}{2}$

step 3

Compare the slopes

$m_A=\frac{2}{3}$

$m_B=-\frac{3}{2}$

The slopes are opposite reciprocal (the product is equal to -1)

therefore

These two lines are perpendicular

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4 years ago