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Elan Coil [88]
3 years ago
12

the coefficient of static friction between a book and the level surface it slides on is 0.65. If the mass of the book is 0.2 kg,

what minimum initial applied force is required to slide the books across the surface?
Physics
1 answer:
aliya0001 [1]3 years ago
6 0

Fs = Us * Fn

Fn = .2*9.8

Fs = 0.65*1.96

Fs = 1.274 N

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2 m/s²

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2 m/s²

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What is the momentum of a 1550kg car that is traveling 38.0 m/s?
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A cat dozes on a stationary merry-go-round, at a radius of 5.5 m from the center of the ride. Then the operator turns on the rid
bixtya [17]

Answer:

u_{s}=0.56

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Where the r is the radius of merry-go-round and v is the tangential speed

but

F_{s.max}=u_{s}F_{N}=u_{s}mg

So we have

u_{s}mg=\frac{mv^2}{r}\\ u_{s}=\frac{v^2}{gr}\\ Where\\v=\frac{2\pi R}{T} \\So\\u_{s}=\frac{(\frac{2\pi R}{T} )^2}{gr} \\u_{s}=\frac{4\pi^2 r}{gT^2}

Substitute the given values

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6 0
3 years ago
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gizmo_the_mogwai [7]

Answer: Smaller than ; larger than

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When the elevator is moving in the upward direction, then the force acting on it is negative in nature because of

N= mg +ma, (g is gravity and a is acceleration)

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Hence, it feels smaller than its original weight.

When the elevator is moving downward , then the force acting will be positive in nature

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here ma will be positive so it feels larger the original weight of passenger.

7 0
3 years ago
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