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Elan Coil [88]
3 years ago
12

the coefficient of static friction between a book and the level surface it slides on is 0.65. If the mass of the book is 0.2 kg,

what minimum initial applied force is required to slide the books across the surface?
Physics
1 answer:
aliya0001 [1]3 years ago
6 0

Fs = Us * Fn

Fn = .2*9.8

Fs = 0.65*1.96

Fs = 1.274 N

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. A huge pile of leaves was wrapped in a tarp in the middle of a lawn. The wrapped leaves weigh 580 newtons. The coefficient of
Rina8888 [55]

The force required is 319 N

Explanation:

The force of static friction is a force that acts an object on a surface, when this object is pushed by another force to put it in motion. The direction of the force of friction is opposite to the direction of the force of push, and its value increases as the force of push increases, up to a maximum value given by:

F_f = \mu W

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\mu is the coefficient of friction

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Therefore, in order to put the object in motion, the force applied must be greater than this value.

For the pile of leaves in this problem, we have:

\mu = 0.55 (coefficient of friction)

W=580 N (weight of the leaves)

Substituting, we find:

F=(0.55)(580)=319 N

Learn more about force of friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

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#LearnwithBrainly

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