To develop this problem it is necessary to apply the concepts related to the Cross Product of two vectors as well as to obtain the angle through the magnitude of the angles.
The vector product between the Force and the radius allows us to obtain the torque, in this way,
Therefore the torque on the particle about the origen is 50k
PART B) To find the angle between two vectors we apply the definition of the dot product based on the vector quantities, that is,
Therefore the angle between the ratio and the force is 103.88°
Answer:
Explanation:
heat lost by coffee = heat gain by aluminum spoon
heat lost by coffee = mc ( 85° C - T)
175 ml of water = 175 grams
175 grams = (175 / 1000) kg = 0.175 kg
heat loss by coffee = 0.175 × 4182 J/Kgk ( 85 - T) = 731.85 ( 85-T) = 62207.25 - 731.85 T
heat gain by aluminum spoon = 0.012kg × 897 J/kgK ( T - 22) = 10.764 T - 236.808
10.764 T - 236.808 = 62207.25 - 731.85 T
10.764 T + 731.85 T = 62207.25 + 236.808
T = 84.086 ° C approx 84°C
Answer:
The mass of the mud sitting above a 3.4
area of the valley floor is 31700 kg
Explanation:
Please find attached the explanation to the answer given above. Thank you.
Answer:
4 times that of nitrogen gas, N2.
Explanation:
Let R1 be the rate of diffusion of nitrogen gas, N2.
Let R2 be the rate of diffusion of Hydrogen gas, H2.
Let M1 be the molar mass N2
Let M2 be the molar mass of H2.
Next, we shall determine the molar mass of N2 and H2.
This is illustrated below below:
Molar mass of N2 (M1) = 2 x 14 = 28 g/mol
Molar mass of H2 (M2) = 2 x 1 = 2 g/mol
Finally, we shall determine the rate of diffusion of Hydrogen gas, H2 as follow:
R1/R2 = √(M2/M1)
M1 = 28
M2 = 2
R1/R2 = √(M2/M1)
R1/R2 = √(2/28)
R1/R2 = √(1/14)
R1/R2 = 0.27
Cross multiply
R1 = R2 × 0.27
Divide both side by 0.27
R2 = R1/0.27
R2 = R1 × 1/0.27
R2 = R1 × 4
R2 = 4R1
Therefore, the rate of diffusion of H2 (R2) is 4 times that of N2 (R1)
