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Klio2033 [76]
3 years ago
10

(i) What is the acceleration of an object between 0-4 seconds?

Physics
1 answer:
DENIUS [597]3 years ago
4 0

Answer:

Your small tiny face

Explanation:

HIHIHIIHHI

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An electron is released from rest in a uniform electric field. The electron accelerates vertically upward, traveling 4.50 m in t
Softa [21]

Answer:

Explanation:

A. Using

E= ma/q

E=m/q(2s/t²)

So

E= 9.1x10^-31/1.6*10^-19( 2*4.5/ 3*10-12)

E=5.7NC

The electric field has to be downward since the force is positive that is upward

B.

The electron acceleration is of the order of 10^11 times greater so for practical purposes we neglect the effect of gravity

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3 years ago
Hello please help i’ll give brainliest
andriy [413]

Answer:

It should be (A few centimeters per year) About three to five centimeters

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What is your hypothesis (or hypotheses) for this experiment?
Ad libitum [116K]

Answer: In that case, Put something like "My hypothesis is that the car will take (x) seconds to get to checkpoint 1, (x) seconds to get to checkpoint 2, (x) seconds to get to checkpoint 3, and (x) seconds to get to checkpoint 4" Replacing x with random numbers, or number close to the actual found numbers, but honestly as long as the guesses arent outrageous you should get the question right

Explanation:

6 0
3 years ago
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Two masses are separated by a distance r. If this distance is doubled, is the force of interaction between the two masses double
baherus [9]

Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

This is mathematically represented as

<u>F= (G X m1 x m2) /r∧2</u>

where F is the force acting between the charged particles

r is the distance between the two charges measured in m

G is the gravitational constant which has a value of <em>6.674×10^-11 Nm^2 kg^-2</em>

m1 and m2 are the masses of the objects measured in Kg

Now if the distance between the is doubled then r becomes 2r. Substituting this in the above formula we get the new Force as

Force (new) = (G X m1 x m2) /(2r)∧2


Thus dividing Force(new)/Force we get

Force(new)/Force = 1/4.

Thus the gravitational force becomes 1/4th of the original value if the distance between the two masses are doubled.




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3 years ago
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Which of the following shows the units of angular motion?
Whitepunk [10]

Answer:

  • The units are <em>(</em><em>rad</em><em>/</em><em>s</em><em>^</em><em>2</em><em>)</em><em> </em>
4 0
3 years ago
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