(i) What is the acceleration of an object between 0-4 seconds?

How are light/radio and infrared waves used in space?

dalvyx [7]

The other types of EM radiation that make up the electromagnetic spectrum are microwaves, infrared light, ultraviolet light, X-rays and gamma-rays. ... Inspace, infrared light helps us map the dust between stars. Visible: Our eyes detect visible light. Fireflies,light bulbs, and stars all emit visible light.

5 0

3 years ago

The video shows an animated billiards experiment in which a cue ball strikes a glued-in-place eight-ball. which of the following

riadik2000 [5.3K]

Suppose object A is a cue ball and object B is an eight ball on a pool table. If the cue ball strikes the eight ball, the cue ball exerts a force on the eight ball that sends it rolling toward the pocket. At the same time, the eight ball exerts an equal and opposite force on the cue ball that brings it to a stop. Note that both the cue ball and the eight ball each experience a change in momentum. However, the sum of the momentum of the cue ball and the momentum of the eight ball remains constant throughout.

8 0

3 years ago

A baseball is thrown straight up. the drag force is proportional to v2. part a in terms of g, what is the y-component of the bal

steposvetlana [31]

At the position of terminal speed the net acceleration of the ball will become zero

As we know that terminal speed will always reach when net force on the ball is zero and its speed will become constant.

So here at this position we can say

$F_d = F_g$

$kv^2 = mg$

$v =\sqrt{\frac{mg}{k}}$

now when ball is moving at half of the terminal speed in upward direction then net force on the ball in downwards direction will be

$F_{net} = mg + F_d$

$F_{net} = mg + kv^2$

here speed of the ball is half of the terminal speed

$v = \frac{1}{2}*\sqrt{\frac{mg}{k}}$

then we have

$F_{net} = mg + k*\frac{mg}{4k}$

$F_{net} = \frac{5mg}{4}$

now acceleration will be given as

$a = \frac{F_{net}}{m}$

now we have

$a = \frac{5g}{4}$

$a = 12.25 m/s^2$ downwards

7 0

4 years ago

Determine the velocity (in m/s) of the object at 10seconds. Include a numerical answer accurate to the first decimal place. If n

tatuchka [14]

Answer:

v = 0.5 [m/s]

Explanation:

In order to determine the speed in such a time interval, we must calculate the slope between the last two positions.

The slope of a line is determined by the following mathematical expression.

P₂ = point 2 = (12,12) = (x₂,y₂)

P₁ = Point 1 = (6,9) = (x₁,y₁)

In this specific case, we must see that in the x-axis we have time, and on the y-axis, we have the space axis.

Now using the slope:

$m =\frac{y_{2} -y_{1} }{x_{2} -x_{1} } \\m = \frac{12-9}{12-6}\\m = 0.5$

This slope is equal to the speed (velocity)

v = 0.5 [m/s]

8 0

3 years ago

How much energy, in joules, is released when 17 kilograms of granite is cooled from 45°C to 21°C?

zepelin [54]

The final answer is -322, 320 Joules. The solution for the problem is:

The equation that must be used in this problem is:

U = mCp(Tf-Ti)

where:
U = energy released or absorbed in Joules
m = mass in kg
Cp = specific heat of material in J/kg-C
Tf = final temperature, C
Ti = initial temperature, C

Looking up the Cp of granite gives a value of 790 J/kg-C.

U = 17kg (790 J/kg-C) (21-45)
U = - 322, 320 Joules (negative means heat is released)

4 0

4 years ago

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