Rw/Ra = MA
18cm/2cm= MA
MA = 9
This means that Fi is 1/9 of the force applied to the axil. The distance travelled by Rw is 9 times more than Ri is that you move 9 times more when turning the wheel using Rw.
Put more simply
Rw/Ra = Fa/Fw
- Rw = Radius of the wheel
- Ra = Radius of the axil
- Fa = Force delivered on the axil
- Fw = Force delivered by the wheel
Answer:
Increase air resistance
Explanation:
Gravity forces the parachute down but air resistance pushing up on the flat surface of the parachute causes it to fall slower to the ground.
Your answer is 5000 J
when W(work) = F X when F= the force and X= the displacment
and F(g) = M a(g) when M= mass and a = the acceleration and in our question
, the force is the gravitational force and a= 9.8 m/S2 we can assume as 10 m/s2
and when we have M= 50 Kg
so by substitution:
F= 50 x 10 = 500 N
and by substitution in work equation: when x = 10 m
∴ W = 500 x 10 = 5000 j
d = distance the bowling ball has fallen = ?
g = acceleration due to gravity acting on the ball by earth = 9.8 m/s²
t = time of fall for the ball = 3.0 s
distance the ball has fallen is given as
d = (0.5) g t²
inserting the above values in the equation above
d = (0.5) (9.8 m/s²) (3.0 s)²
d = (0.5) (9.8 m/s²) (9.0 s²)
d = (4.9 m/s²) (9.0 s²)
d = 44.1 m
hence the distance fallen by the ball comes out to be 44.1 m
Answer:
v = K √(E / ρ)
Explanation:
Modulus of elasticity has units of N/m², or kg/m/s².
Density has units of kg/m³.
Velocity has units of m/s.
If we divide modulus of elasticity by density, we can eliminate kg:
E / ρ = [kg/m/s²] / [kg/m³]
E / ρ = [m²/s²]
Taking the square root gets us units of velocity:
√(E / ρ) = [m/s]
Multiply by the constant K:
v = K √(E / ρ)
