Answer:
Y=240sin(180πx)
Step-by-step explanation:
All i really looked at was the last part 180πx since it was running 90 cycles per second my natural instinct was to do this
90 times 2π and i got 180π
Answer:
TRUE
Step-by-step explanation:
A quadratic equation can be found that will go through any three distinct points that ...
- satisfy the requirements for a function
- are not on the same line
_____
The key word here is "may." You will not be able to find a quadratic intersecting the three points if they do not meet both requirements above.
Answer:
the domain is {7,-4,1,4,}
the range is {1,-5,2,-7}
Step-by-step explanation:
For the first one, you do need to divide. The division should be: 286/26, to find how many invitations can be printed each minute.
286/26=11
The answer is C. 11 invitations can be printed each minute.
For the second problem, Amy runs 1 mile every 7.5 minutes. To find how many miles she runs in an hour, divide 7.5 by 60:
60/7.5=8
The answer is G. Amy runs 8 miles in an hour.
I hope this helps :)
Answer:
![\hat p \sim N (p , \sqrt{\frac{p(1-p)}{n}})](https://tex.z-dn.net/?f=%5Chat%20p%20%20%5Csim%20N%20%28p%20%2C%20%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D%29%20)
The mean is given by:
![\mu_{\hat p} = 0.55](https://tex.z-dn.net/?f=%20%5Cmu_%7B%5Chat%20p%7D%20%3D%200.55)
And the deviation:
![\sigma_{\hat p} =\sqrt{\frac{0.55*(1-0.55)}{953}}= 0.0161](https://tex.z-dn.net/?f=%20%5Csigma_%7B%5Chat%20p%7D%20%3D%5Csqrt%7B%5Cfrac%7B0.55%2A%281-0.55%29%7D%7B953%7D%7D%3D%200.0161)
Step-by-step explanation:
For this case we assume that the true population proportion of Americans do not know that GOP stands for Grand Old Party is 0.55 and we select a random sample of n = 953 americans
For this case we assume that we satisfy the conditions to use the normal approximation for
1) np >10 , n(1-p)>10
2) Independence
3) Random sample
4) The sample size is less than 10% of the population size
We assume that all the conditions are satisfied and the distribution for
would be:
![\hat p \sim N (p , \sqrt{\frac{p(1-p)}{n}})](https://tex.z-dn.net/?f=%5Chat%20p%20%20%5Csim%20N%20%28p%20%2C%20%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D%29%20)
The mean is given by:
![\mu_{\hat p} = 0.55](https://tex.z-dn.net/?f=%20%5Cmu_%7B%5Chat%20p%7D%20%3D%200.55)
And the deviation:
![\sigma_{\hat p} =\sqrt{\frac{0.55*(1-0.55)}{953}}= 0.0161](https://tex.z-dn.net/?f=%20%5Csigma_%7B%5Chat%20p%7D%20%3D%5Csqrt%7B%5Cfrac%7B0.55%2A%281-0.55%29%7D%7B953%7D%7D%3D%200.0161)