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Hitman42 [59]
3 years ago
13

A parabola has a vertex at (4, 0) and passes through the point (6, 1). What is the equation of the parabola?

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
7 0
We are given the vertex of  a parabola equal to (4, 0) and that the passes the point (6,1). In this case, it is assumed from the given that the parabola is facing upwards. In this case, the equation is (y-k) = 4a (x-h)^2 ; y = 4a (x-4)^2 when x is 6 and y is 1. then, 
 1 = 4a (6-4)^24a is equal to 1/4
the equation then is y = 1/4 (x-4)^2
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Please help! I’ll mark Brainlyest
denpristay [2]

Answer:

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Step-by-step explanation:

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Tasya [4]

Answer:

a

Step-by-step explanation:

4 0
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Read 2 more answers
Given the polygon containing Point P.
Fynjy0 [20]
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7 0
3 years ago
Drag and drop the reasons for the steps into each box correctly to solve the equation
Viktor [21]

Yes your answers are correct :)

Step by step review:

First line has product of 5 and (x+2) so product property is good.

2nd line has division so quotient property is good.

3rd line has equal log with base 2 so equality property is good.

4th line has multiplication so that is also good

5th line has distribution of 5 and 7 so distributive property is good.

Your answer is correct.

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